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frutty [35]
3 years ago
7

What is the the equation 2/3n = 7/8​

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
4 0

Solve for n

by simplifying both sides of the equation, then isolating the variable.

n = 21/16

Decimal Form:

1.3125

Mixed Number Form:

1 5/16

hope this helped

Lina20 [59]3 years ago
3 0

Answer:

n = \frac{21}{16}

Step-by-step explanation:

Given

\frac{2}{3} n = \frac{7}{8}, that is

\frac{2n}{3} = \frac{7}{8} ( cross- multiply )

16n = 21 ( divide both sides by 16 )

n = \frac{21}{16}

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Hey there!

The answer is: Fourteen Point Eight Hundred Ninety-Five Thousandths

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What is the difference between the number of families that use 2 computers to the number of families that own 0 or 4 computers
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4 years ago
the problitiy is that a sweet stawberry flavor is 0.8 what is the problity is that a sweet is orang flavor what is anwer
dsp73

Answer:

\huge\boxed{Answer\hookleftarrow}

Assuming that there are only 2 flavors of the sweet ⇻ strawberry & orange.

____________________

P (strawberry flavored sweet) = 0.8

P (orange flavored sweet) = ?

____________________

Now, we know that ➳ the value of probability ≤ 1. So, the probability of orange flavored sweets is less than 1.

____________________

So,

P (orange flavored sweet) = 1 - P (strawberry flavored sweet)

P (orange flavored sweet) = \large\bold{1.0 - 0.8}

P (orange flavored sweet) = \large\bold{0.2}

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✐ The probability that the sweet is orange flavored is <u>0</u><u>.</u><u>2</u>

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ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

4 0
3 years ago
Many elementary school students in a school district currently have ear infections. A random sample of children in two different
Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school n_1 = 42

sample size for the second school n_2  = 34

so 16 out of 42 i.e x_1 = 16 and 18 out of 34 i.e x_2 = 18 have ear infection.

the proportion of students with ear infection Is as follows:

\hat p_1 = \dfrac{16}{42} = 0.38095

\hat p_2 = \dfrac{18}{34}  =  0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}

\bar p = \dfrac{16 +18}{42 +34}

\bar p = \dfrac{34}{76}

\bar p = 0.447368

\bar p + \bar  q = 1 \\ \\ \bar q = 1 -\bar  p \\  \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632

The pooled standard error can be computed by using the formula:

S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} +  \dfrac{\bar p \bar p}{n_2} }

S.E = \sqrt{ \dfrac{  0.447368 *  0.552632}{ 42} +  \dfrac{ 0.447368 *  0.447368}{34} }

S.E = \sqrt{ \dfrac{  0.2472298726}{ 42} +  \dfrac{ 0.2001381274}{34} }

S.E = \sqrt{ 0.01177284105}

S.E = 0.1085

The test statistics is ;

z = \dfrac{\hat p_1 - \hat p_2}{S.E}

z = \dfrac{0.38095- 0.5294}{0.1085}

z = \dfrac{-0.14845}{0.1085}

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0
4 years ago
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