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svp [43]
3 years ago
9

HELP FAST giving 5 stars

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

The red is 1/3 and yellow is 1/4

Step-by-step explanation:

there are 3 colors and 1 of them is red so 1/3 same goes to the yellow 4 colors and  is 1 yellow so 1/4

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Find the coordinates of the midpoint of<br> segment XY for X(-2, 3) and Y(-8, -9).
marshall27 [118]

Answer:

use formula

(x,y) =[ (x1+x2)/2 ,(y1+y2/2)]

=[(-2-8)/2, (3-9)/2]

=(-10/2 ,-6/2)

=(-5,-3)

4 0
3 years ago
The longest side of an obtuse triangle measure 20 cm. the two shorter sides measure x cm.and 3x sm round to the nearest tenth,wh
sleet_krkn [62]

22cm is the greatest

It should be greater than17(20-3)

and smaller than 23(20+3)


5 0
3 years ago
I really need help with this dividend thing. Plz help ASAP
dimaraw [331]

Answer:

45.26

Step-by-step explanation:

36.50 \times 73 = (2664.5) \div 50  \\ = 53.29

53.29 \times 62 = (3303.98) \div 73 \\  = 45.26

4 0
3 years ago
68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se
Mnenie [13.5K]

Answer:

\boxed{\bf\: The  \: park  \: sold  \boxed{ 34{}} \: child  \: tickets.}

Step-by-step explanation:

<u>Given:</u>

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

<u>To </u><u>Find:</u>

The Number of child tickets the park sold.

<u>Solution:</u>

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

\sf \:  =  \:  \cfrac{68}{100}  \times 50

<u>Note</u>:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: <u>Cancel One zero of 50 and one zero of 100,That is</u>:-

\sf =  \cfrac{68}{ 10\cancel0}  \times 5 \cancel0

<em>Results to,</em>

\sf  = \cfrac{68}{10}  \times 5

Step 3: <u>Cancel 5 and 10, That is</u>:-

\sf  = \cfrac{68}{ \cancel{10 }}  \times  \cancel5

<em>Results to,</em>

\sf =\:  \cfrac{68}{2}  \times 1

\sf = \cfrac{68}{2}

Step 4: <u>Cancel 68 and 2, That is</u>:-

\sf =\:  \cfrac{ \cancel{68}}{ \cancel2}

<em>Results to,</em>

\sf  =  \cfrac{34}{1}

\sf  = 34

34 is the result.

Hence,

\underline{ \rm \: The  \: park  \: sold  \: \bold{ 34 } \: child  \: tickets.}

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0
2 years ago
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the h
Mama L [17]

The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively

<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3>

<u>Juan</u>

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

<u>Mark</u>

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

<u>Barry</u>

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

<h3>The height the balls hit a fence at 350 ft distance</h3>

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

Read more about quadratic functions at:

brainly.com/question/12446886

#SPJ1

4 0
1 year ago
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