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4 years ago

Equivalent fractions 2/4 3/6 4/8 5/10

1 answer:

6 0

4/8
6/12
8/16
10/20
all you have to do is multiply both sides by 2, or 3, etc
if im remembering that right, i did this forever ago.

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High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

Step:-1

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

Step(ii):-

Degrees of freedom = n-1 =9-1 =8

t₀.₀₀₅ = 3.3554

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

Final answer :-

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

4 0

3 years ago

Consider the geometric sequence: 3, 15, 75, 375, 1875 ... 1. What is the constant ratio, r, for this sequence? 2. Use r to write

zalisa [80]

R= 5

$a_{n} =3* 5^{n-1}$

7 0

3 years ago

Read 2 more answers

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0

3 years ago

Long division 4840÷90 help!

coldgirl [10]

53.778 is the answer. I hope this helps and have a good day!

5 0

3 years ago

Increase £84 by 3% thank you!

Alex777 [14]

If you would like to increase £84 by 3%, you can calculate this using the following steps:

3% * £84 = 3/100 * 84 = £2.52

£84 + £2.52 = £86.52

The correct result is £86.52.

8 0

3 years ago