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hjlf
4 years ago
12

Equivalent fractions 2/4 3/6 4/8 5/10

Mathematics
1 answer:
kow [346]4 years ago
6 0
4/8
6/12
8/16
10/20
all you have to do is multiply both sides by 2, or 3, etc 
if im remembering that right, i did this forever ago.
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High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
Consider the geometric sequence: 3, 15, 75, 375, 1875 ... 1. What is the constant ratio, r, for this sequence? 2. Use r to write
zalisa [80]
R= 5

a_{n} =3* 5^{n-1}


7 0
3 years ago
Read 2 more answers
An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
3 years ago
Long division 4840÷90 help!
coldgirl [10]
53.778 is the answer. I hope this helps and have a good day!
5 0
3 years ago
Increase £84 by 3%<br> thank you!
Alex777 [14]
If you would like to increase £84 by 3%, you can calculate this using the following steps:

3% * £84 = 3/100 * 84 = £2.52

£84 + £2.52 = £86.52

The correct result is £86.52.
8 0
3 years ago
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