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hjlf
3 years ago
12

Equivalent fractions 2/4 3/6 4/8 5/10

Mathematics
1 answer:
kow [346]3 years ago
6 0
4/8
6/12
8/16
10/20
all you have to do is multiply both sides by 2, or 3, etc 
if im remembering that right, i did this forever ago.
You might be interested in
#16 i
Vlad1618 [11]

The tuition is an illustration of a linear function.

The cost of tuition and fees in the academic year 2023-2024, is $12260

Let the number of academic years after 2014-2015 academic year be x.

So, we have:

\mathbf{(x,y) \to (0,9200)(5,10900)}

A linear function is represented as:

\mathbf{y = mx + b}

Where m represents the slope (i.e. constant rate), and b represents the y-intercept (i.e. the value of y when x = 0)

So, we have:

\mathbf{10900 = 5m + 9200}

Subtract 9200 from both sides

\mathbf{1700 = 5m}

Divide both sides by 5

\mathbf{340 = m}

So, we have:

\mathbf{m =340 }

The function becomes

\mathbf{y = mx + b}

\mathbf{y = 340x + 9200}

In the academic year 2023-2024, x = 9.

So, we have:

\mathbf{y = 340x + 9200}

\mathbf{y = 340 \times 9 + 9200}

\mathbf{y = 3060 + 9200}

\mathbf{y = 12260}

Hence, the cost of tuition and fees is $12260

Read more about linear functions a:

brainly.com/question/21107621

4 0
3 years ago
At a zoo, for every 6 Adult camels, there are 5 baby camels. There are a total of 44 adult and baby camels at the zoo
OleMash [197]
Whats the question asking its just a statement. there would be 4 groups of camels 6+5=11•4=44
8 0
3 years ago
The number of bacterial cells, B, in a container after t hours is given by B=25x2t After how many hours will there be 400 bacter
Nikitich [7]

Answer:

8 hours

Step-by-step explanation:

We have that;

B = number of bacterial cells, B, in a container after t hours

t = time taken in hours

The function is;

B=25x2t

Where B = 400 bacterial cells

400 = 25x2t

t = 400/25x2

t = 8 hours

5 0
3 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
What is the simplest form of 4a + 8b/12​<br> Step by step pls
shutvik [7]

Answer:

4a + 2b/3

Step-by-step explanation:

focus on 8b/12 first:

factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3

then, go back to 4a:

4a is in its simplest form, it can't be factor

therefore, plus 4a and 2b/3 = 4a + 2b/3

5 0
3 years ago
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