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Iteru [2.4K]
3 years ago
12

What is a real number between 13 and 14 square root

Mathematics
1 answer:
love history [14]3 years ago
3 0
There are many answers, but one is 3.654
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What is the slope of the line that passes through the following points: (3,-1) and (-1,2)?
Katyanochek1 [597]

with the equation of the slope for two points given, m=Y2-Y1/ X2-X1, you can obtain the slope , x1= 3, y1 = -1 , x2= -1, y2= 2  

m = 2-(-1)/ -1-3 ⇒ m= 3/-4, m = -3/4, therefore the slope is - 3/4


7 0
3 years ago
A. 3<br> B. -3/4<br> C. -1<br> D. 2
yawa3891 [41]
B
because rise over run
6 0
3 years ago
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A student’s first step to solving the equation 5(x – 2) = 10 was to simplify it to 5x – 2 = 10. Did the student make a mistake?
Dafna11 [192]
Yes, he forgot to distribute all the terms. 

3 0
4 years ago
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Write the equation for a line perpendicular to a line passing through points (-1,2) and (1,-8)
soldi70 [24.7K]

Answer:

Step-by-step explanation:

Slope m = (-8-2)/(1+1)=-10/2 = -5

Perpendicular slope-1/m = -1/-5 = 1/5

Equation of a line with perpendicular slope is

y-y1=(-1/m)(x-x1)

y - 2 = (1/5)(x+1)

y =2 +(1/5)(x+1)

3 0
3 years ago
Solve for m.<br> 8m+95&lt;−87m+5
tiny-mole [99]

Answer:

m < -\frac{18}{19}

Step-by-step explanation:

8m + 95 < -87m + 5

8m + 87m < 5 - 95

95m < -90

m < -<u>\frac{90}{95}</u>

Simplifying gives;

m < -\frac{18}{19}

3 0
3 years ago
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