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kupik [55]
3 years ago
8

Factor -5a^2b + 10ab^2 - 20b + 25a^3b

Mathematics
2 answers:
Daniel [21]3 years ago
6 0
For this case we have the following expression:
 -5a ^ 2b + 10ab ^ 2 - 20b + 25a ^ 3b
 We observe that the term 5b is repeated throughout the expression,
 therefore it is a common factor.
 So, factoring we have:
 5b (-a ^ 2 + 2ab - 4 + 5a ^ 3)
 Then, rewriting we have:
 5b (a ^ 2 (5a-1) + 2ab-4)
 Answer:
 
The factored expression is given by:
 
5b (a ^ 2 (5a-1) + 2ab-4)
marysya [2.9K]3 years ago
4 0
Factor out the GCF, which is 5b, and you get: 5b(5a^3-a^2+2ab-4)
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Wich is bigger<br><br> 1.320. 1.302<br><br> &lt;<br> &gt; <br> =
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3 years ago
Can someone help me with please??​
OverLord2011 [107]

Answer:

The angle is 35 degrees

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Since this is an isosceles triangle, we know that the two remaining angles must be the same. Set those angles equal to x. Now, we can solve for x by adding those two angles to the third angle and setting equal to 180.

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6 0
3 years ago
A product comes in cans labeled "38 oz". A random sample of 10 cans had the following weights:
KiRa [710]

Answer:

b. 35.9, 39.1 ounces

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

barX=37.465 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=2.27 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

barX +- t*[(s)/(sqrt{n))]   (1)

In order to calculate the critical value t we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_(alpha/2)=2.26

Now we have everything in order to replace into formula (1):

37.465-2.26[(2.27)/(sqrt{10))]=35.9    

37.465+2.26[(2.27)/(sqrt{10))]=39.1

So on this case the 95% confidence interval would be given by (35.9;39.1)    

7 0
4 years ago
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