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3 years ago

Factor -5a^2b + 10ab^2 - 20b + 25a^3b

2 answers:

6 0

For this case we have the following expression:
-5a ^ 2b + 10ab ^ 2 - 20b + 25a ^ 3b
We observe that the term 5b is repeated throughout the expression,
therefore it is a common factor.
So, factoring we have:
5b (-a ^ 2 + 2ab - 4 + 5a ^ 3)
Then, rewriting we have:
5b (a ^ 2 (5a-1) + 2ab-4)
Answer:
The factored expression is given by:
5b (a ^ 2 (5a-1) + 2ab-4)

marysya [2.9K]3 years ago

4 0

Factor out the GCF, which is 5b, and you get: 5b(5a^3-a^2+2ab-4)

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3 years ago

Thais goes to the store and buys 23 muffins that cost 3 dollars each. She then buys 12 cakes that cost 18 dollars each. How much

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216 spent on cakes

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

PLZ TELL ME IF THIS IS RIGHT!!! THX

emmasim [6.3K]

Answer:

correct

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5 0

3 years ago

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

So, no option is correct. And the answer is

$T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

Learn more about linear transformations here-

brainly.com/question/13005179

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5 0

2 years ago

Fran has 7 sheets of paper for a colouring project. If she only uses 1/3 of a sheet of paper per drawing how many drawings can s

Sav [38]

So we can make an equation for this, being 7=1/3x, as that effectively says she can make 3 drawings per page.

Knowing this, we can multiply it by 3 to get x=21 (since if she can draw 3 drawings per page, we can imagine that if each drawing took a page she would need 3 times the pieces of paper), therefore she can make 21 drawings.

8 0

3 years ago