All categories

2 years ago

Factor -5a^2b + 10ab^2 - 20b + 25a^3b

2 answers:

6 0

For this case we have the following expression:
-5a ^ 2b + 10ab ^ 2 - 20b + 25a ^ 3b
We observe that the term 5b is repeated throughout the expression,
therefore it is a common factor.
So, factoring we have:
5b (-a ^ 2 + 2ab - 4 + 5a ^ 3)
Then, rewriting we have:
5b (a ^ 2 (5a-1) + 2ab-4)
Answer:
The factored expression is given by:
5b (a ^ 2 (5a-1) + 2ab-4)

marysya [2.9K]2 years ago

4 0

Factor out the GCF, which is 5b, and you get: 5b(5a^3-a^2+2ab-4)

You might be interested in

△ABC has interior angles with measures x°, 100°, and 70°, and △DEF has interior angles with measures y°, 70°, and 50°.

Vikentia [17]

Hey there! :D

We know that the triangles are not similar. If they were, they would have the same angles. The interior angles are not congruent. We can rule out choice "B" and "C".

Just because they have one equal angle does not make them similar. We can rule out "D".

"A" is the best answer.

I hope this helps!
~kaikers

3 0

3 years ago

Read 2 more answers

Find the value of x in the triangle shown below 8 2

Anit [1.1K]

Answer:

8.25

Step-by-step explanation:

(8x 8) + (2x2) = x ^2

64 + 4 = x2

x = √68

x = 8.25

3 0

3 years ago

Given P=1/2x(y+z),find the value of P,if x=6 and y=9 and z=7

GREYUIT [131]

<span>P=1/2 x(y+z)
</span><span>P=1/2 (6)[9 + 7]
P = 3(16)
P = 48

hope it helps</span>

8 0

3 years ago

Put these numbers in order from smallest to biggest. Standard form need help ASAP!!

SSSSS [86.1K]

C because when you expand all the numbers, they go in the same order as c has them.

8 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago