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Elis [28]
3 years ago
9

 what is the answer of -72 ÷ -6

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0
The quotient of negative 72 and negative 6 is equal to 12.
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7/18 divided by 5/6. For a practice buddy
kenny6666 [7]

Answer:

0.46666666666

Step-by-step explanation:

i tried

7 0
3 years ago
Simplify 4^3 • 4^5 <br> a 4^8<br> b 16•15<br> c 4^15<br> d 16^8
user100 [1]

Answer:

4^8

Step-by-step explanation:

keep base (which is 4) and add exponents when multiplying

3 0
3 years ago
which decription best compares the graphs of these two functions? y = -3x + 2 and x- 0, 2, 4 ,6 y- 2, 1, 0, -1
loris [4]
Y=-6 i think this is the answer
8 0
3 years ago
The data below represents the overall miles per gallon​ (MPG) of 2008 SUVs priced under​ $30,000.
nevsk [136]

Answer:

99% Confidence interval: (17.9064,19.8136)

Step-by-step explanation:

We are given the following data set:

22,18,19,21,18,19,18,17,20,20,18,17,20,19,20,18,17,18,16,21,18,21

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{415}{22} = 18.86

Sum of squares of differences = 52.59

S.D = \sqrt{\frac{52.59}{21}} = 1.58

99% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 21 and}~\alpha_{0.01} = \pm 2.831  

18.86 \pm 2.831(\frac{1.58}{\sqrt{22}} ) = 18.86 \pm 0.9536 = (17.9064,19.8136)

Option A) With 99​% ​confidence, the mean miles per gallon in the population of 2008 SUVs is somewhere in the interval.

4 0
4 years ago
Which data set could be represented by the box plot shown below?
jarptica [38.1K]

Answer:

choice a

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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