What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Answer:
4
Step-by-step explanation:
split it in half u get a subtract sing makes that (8-4=4)
A quantity is said to be determined by exponential decay if it diminishes at a rate proportional to its value. The time essential for the decaying amount to descend to half of its initial value. Therefore the answer<span> is False.</span>
The right answer for the question that is being asked and shown above is that: "Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis." The description best describes the solution to the system of equations is that <span>Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis</span>
Answer:
x = 4
m<cdb = 82
Step-by-step explanation:
The exterior angle thm states that the exterior angle of a triangle is equal to the sum of the opposite interior angles:
7x + 2 + 17x = 98
24x + 2 = 98
24x = 96
x = 4
m<cdb =
y + 98 = 180
y = 180 - 98
y = 82