Solve the inequality -2(k+3) < -2k - 7
1 answer:
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Answer:
Answer
Given polynomial- 5x
7
−6x
5
+7x−6
Here,
(a) Coefficient of x
5
=−6
Coefficient of x
2
=0
(b) Degree of polynomial = highest degree of monomial with non-zero coefficient =7
(c) Constant term = Coefficient of x
0
=−6
(d) Number of terms =4
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• First way to solve:
We'll manipulate the expression of the equation:
If we have y=0:
Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).
Answer: B
• Second way to solve:
The degree of the function is 3. So, the function has 3 complex zeros.
Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)
The function "has only one non-repeated x-intercept", then there is only one real zero.
The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.
Answer: B.
We'll manipulate the expression of the equation:
If we have y=0:
Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).
Answer: B
• Second way to solve:
The degree of the function is 3. So, the function has 3 complex zeros.
Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)
The function "has only one non-repeated x-intercept", then there is only one real zero.
The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.
Answer: B.