Answer:
The answer is below
Step-by-step explanation:
a) y=3x-1
The standard equation of a line is given by:
y = mx + c
Where m is the slope of the line and c is the intercept on the y axis.
Given that y=3x-1, comparing with the standard equation of a line, the slope (m) = 3, Two lines with slope a and b are perpendicular if the product of their slope is -1 i.e. ab = -1. Let the line perpendicular to y=3x-1 be d, to get the slope of the perpendicular line, we use:
3 × d = -1
d = -1/3
To find the equation of the perpendicular line passing through (0,0), we use:
![y-y_1=d(x-x_1)\\d\ is\ the \ slope:\\y-0=-\frac{1}{3} (x-0)\\y=-\frac{1}{3}x](https://tex.z-dn.net/?f=y-y_1%3Dd%28x-x_1%29%5C%5Cd%5C%20is%5C%20the%20%5C%20slope%3A%5C%5Cy-0%3D-%5Cfrac%7B1%7D%7B3%7D%20%28x-0%29%5C%5Cy%3D-%5Cfrac%7B1%7D%7B3%7Dx)
To find x if the point P(x, 4) lies on the new line, insert y = 4 and find x:
![y=-\frac{1}{3}x\\ 4=-\frac{1}{3}x\\-x=12\\x=-12](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7Dx%5C%5C%204%3D-%5Cfrac%7B1%7D%7B3%7Dx%5C%5C-x%3D12%5C%5Cx%3D-12)
b) y=1/4 x+2
Given that y=1/4 x+2, comparing with the standard equation of a line, the slope (m) = 1/4. Let the line perpendicular to y=1/4 x+2 be f, to get the slope of the perpendicular line, we use:
1/4 × f = -1
f = -4
To find the equation of the perpendicular line passing through (0,0), we use:
![y-y_1=f(x-x_1)\\f\ is\ the \ slope:\\y-0=-4 (x-0)\\y=-4x](https://tex.z-dn.net/?f=y-y_1%3Df%28x-x_1%29%5C%5Cf%5C%20is%5C%20the%20%5C%20slope%3A%5C%5Cy-0%3D-4%20%28x-0%29%5C%5Cy%3D-4x)
To find x if the point P(x, 4) lies on the new line, insert y = 4 and find x:
![y=-4}x\\ 4=-4x\\x=-1](https://tex.z-dn.net/?f=y%3D-4%7Dx%5C%5C%204%3D-4x%5C%5Cx%3D-1)