I would want to round to the nearest hundred place rather than the nearest tens place because if you round to the nearest hundred place then your answer would be closer to the original answer.
Answer:
y=2x-1
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept
A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
S = 2(LW +H(L +W))
S = 2((4 cm)*(4 cm) +(6 cm)*(4 cm +4 cm))
S = 2(16 cm² +48 cm²)
S = 2*64 cm² = 128 cm²
The surface area of the prism is 128 cm².
Maybe something like 24/4=6. so sorry if I'm incorrect.
Answer:



Step-by-step explanation:
Let
x----> the length of the rectangular garden
y---> the width of the rectangular garden
we know that
The perimeter of the rectangle is equal to

we have

so

simplify

------> equation A
Remember that the area of rectangle is equal to
----> equation B
substitute equation A in equation B
----> this is a vertical parabola open downward
The vertex is a maximum
The y-coordinate of the vertex is the maximum area
The x-coordinate of the vertex is the length side of the rectangle that maximize the area
using a graphing tool
The vertex is the point 
see the attached figure
so

Find the value of y

The garden is a square
the area is equal to
----> is equal to the y-coordinate of the vertex is correct