3 years ago

#Geometry -need help ASAP

Mathematics

1 answer:

Citrus2011 [14]3 years ago

8 0

1 one or A for your geomatyr
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1/3 divided by 1/8<br> a, 1/24<br> b. 3/8<br> C. 2 and 2/3<br> d. 24

Degger [83]

The answer is B. 3/8

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2 years ago

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Recall from Intermediate Algebra that two non-vertical lines are perpendicular if and only if they have negative reciprocal slop

OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is $y = -4 x$

Step-by-step explanation:

From the question we are told that

The line is $y = \frac{1}{4} x + 8$

The point is P(0,0 )

Generally the equation for a line is $yn = mx + c$

Now comparing this with the given equation we see that

$m =\frac{1}{4} = slope$

$C =8 = intercept$

Generally the slope of the perpendicular to the given line is mathematically evaluated as

$m_1 = - \frac{1}{m}$

=> $m_1 = - \frac{1}{ \frac{1}{4}}$

=> $m_1 = -4$

Generally from the univesal equation of a line and the given point we have that

y = mx + c at p(0,0) and $m_1 = -4$ is

0 = -4 (0 ) + c

=> c = 0

Hence the equation perpendicular to the line given at the point given is

$y = -4 x$

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3 years ago

Hal has a square garden in his backyard with an area of 210 square feet. To the nearest half foot, what are the dimensions of th

Zanzabum

I believe the answer is 57sqft

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3 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

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3 years ago

Find the length of the hypotenuse in the figure shown below.

slega [8]

Answer:

the answer is b.13 meters

Step-by-step explanation:

a²+b²=c²

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3 years ago

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