The value of x is 5.4 ( find the description in the picture)
n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.
Here, since we want our ratio in simplest form,
I would use a fraction bar.
Now, the problem asks us to compare
the number of boys to the number of girls.
We know that there are 12 boys
and we know that there are 15 girls.
So our ratio is 12/15.
However, this can be reduced to 4/5.
