Answer:

Step-by-step explanation:
The given function is
![y=\sqrt[3]{x+8}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx%2B8%7D)
The range refers to the values of y for which x is defined.
We solve for x to obtain;


This is a polynomial function in y.
x is defined for all values of y.
Therefore the range is all real numbers.
or

The first choice is correct.
Answer:
8
Step-by-step explanation:
You just gotta divide 64 by 8
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
C is greater than or equal to $40 (which means put the > sign with a line under it).
f(x) = x² - 8x + 5 Plug in -1 for all of the x-values
f(-1) = (-1)² - 8 (-1) + 5 Square -1
f(-1) = 1 - 8 (-1) + 5 Multiply -8 and -1
f(-1) = 1 + 8 + 5 Add
f(-1) = 14