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3 years ago

What is the slope of the graph? (Example: 2/3,-4,-2/9)

Mathematics

1 answer:

Vladimir79 [104]3 years ago

3 0

1/2 ; you must look at rise over run. It goes up by one, runs over 2. 1/2 is a half

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The length of a rectangle is 6cm longer than the width. The perimeter of the rectangle is 92 cm. Find the length of the width of

Vinvika [58]

Answer:

l=26

w=20

Step-by-step explanation:

l-6=w

2l+2w=92

2l+2(l-6)=92

2l+2l-12=92

4l=104

l=26

(26)-6=w

w=20

4 0

2 years ago

Over the past month, a hairstylist has had 28 female clients and 12 male clients. What is the ratio of male clients to female cl

maw [93]

Answer:its A. 3/7 because it would be 12:28 so you'd simplify it.

Step-by-step explanation:

12/28=3/7

4 0

2 years ago

PLZZ HELP ITS AN EMERGENCY THIS IS DUE IN 30 MINUTES!!!

Nataly_w [17]

Answer:

1.equation

2. inverse operations

3. 3.7

4. 8

5. yes its a solution because 58=58

6. not a solution

7. 10.3

9. 9

11. 64

12. 2.1

Step-by-step explanation:

4 0

3 years ago

Simplify question 2 please ASAP !!!!

Mrrafil [7]

Answer:

$\sqrt[3]{ - 0.125} = \sqrt{ - 1} \times \sqrt[3]{0.125 } \\ = 5i$

here i equals √-1

Step-by-step explanation:

Answer is 5i

If you have any doubts write in comments box.

HAVE A NICE DAY !

3 0

2 years ago

find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor

Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: $y = -x^2+8x-12$

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

$y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0$

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

$x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0$

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0

3 years ago