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3 years ago

What is the domain of the function represented in the graph? {t| 0 ≤ t ≤ 14} {h| 0 ≤ h ≤ 210} {t | 0 ≤ t ≤ 210} {h | 0 ≤ h ≤ 14}

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

8 0

The answer is A
<span>{t| 0 ≤ t ≤ 14}</span>

fenix001 [56]3 years ago

8 0

Answer:

A is correct for e2020

Step-by-step explanation:

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Plssss help (the answer choices are the same for all)

Lilit [14]

1) x < 8/3
2) x > -9
3) Infinite Solutions
4) No Solution

Please correct me if I’m wrong. Hope this helps!

3 0

3 years ago

Solve 0 = (x – 4)2 – 1 by graphing the related function.

fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

$y=\left(x-\:4\right)^2-1$

Finding the x-intercept by substituting the value y = 0

$y=\left(x-\:4\right)^2-1$

$\:0\:=\:\left(x\:-\:4\right)^2\:-\:1$ ∵ y = 0

$\left(x-4\right)^2-1=0$

$\left(x-4\right)^2-1+1=0+1$

$\left(x-4\right)^2=1$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$\mathrm{Solve\:}\:x-4=\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=1$

$x=5$

$\mathrm{Solve\:}\:x-4=-\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=-1$

$x=3$

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0

3 years ago

A spinner is split into 4 equal parts labeled 1, 2, 3, and 4.

ivolga24 [154]

Answer:

50%

Step-by-step explanation:

If there are 4 parts to the spinner, 4 is the whole. Since there are 2 even numbers (2&4), the fraction would be $\frac{2}{4}$ , which is simplified to $\frac{1}{2}$ . And because $\frac{1}{2}$ could also turn into $\frac{50}{100}$ , the percentage is 50%.