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Ksivusya [100]
2 years ago
11

Describe 2 ways to find the area of the shaded rectangle

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
3 0
Calculate the area of both shapes. The area of a rectangle is determined by multiplying its length times its width. The area of a circle is Pi (i.e., 3.14) times the square of the radius. Find the area of the shaded region by subtracting the area of the small shape from the area of the larger shape.
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The Mendes family bought a new house 6 years ago for $104,000. The house is now worth $177,000. Assuming a steady rate of growth
dusya [7]
Well, the house grew 73 k throughout the 6 years, so it grew around 12.16 k each year. 12.16/104= approximately 11.6923%
Rounded to the nearest 1/10 of a percent, it's 11.7%
7 0
2 years ago
What is the reference angle for 7pi/6​
max2010maxim [7]

Answer:

\frac{\pi }{6}

Step-by-step explanation:

\frac{7\pi }{6} is in the third quadrant

To find the reference angle subtract π from it, that is

reference angle = \frac{7\pi }{6} - π = \frac{\pi }{6}

8 0
3 years ago
Evaluate: (d + 1)(d - 1 + 6) <br> d = 2
Allisa [31]
F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
3 0
3 years ago
Use the distributive property to write an expression equivalent to 8(35).
Debora [2.8K]

Answer:

280

Step-by-step explanation:

All you have to do is multiply 35 by 8 to get 280.

I am joyous to assist you anytime.

3 0
3 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Eduardwww [97]

Answer:

(A)  H_0 : μ = 22 ; H_A : μ ≠ 22

(B) Value of the test statistic = -2.69

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

We have to test the accuracy of the bottling process.

(A) Let, NULL HYPOTHESIS, H_0 : \mu = 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

ALTERNATE HYPOTHESIS, H_A : \mu \neq 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that will be used here is One-sample z-test;

             T.S. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounces

            n = sample of bottles = 65

(B) So, <u>test statistics</u> =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }

                                  = -2.69

Hence, the value of test statistics is -2.69.

6 0
3 years ago
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