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3 years ago

A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.

2 answers:

7 0

A) using f=ma, F=m1 x 3.00 =3m1
also F=m2 x 1.00 = m2
as the Fs are the same: 3m1=m2
this means that the ratio of m1 to m2 is 3 to 1 as there are 3 m1s for every m2.
b) again using f=ma, the combination of the masses is m1 + m2 or 4m1 as there are 3m1s in m2. so F=4m1 x a = 3m1 (as F is the same for all of them).
a = 3m1/4m1 = 3/4ms^-2

Lerok [7]3 years ago

6 0

A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3

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If x^2 = a and a > 0. what is x?

7nadin3 [17]

$\\ \sf\longmapsto x^2=a$

$\\ \sf\longmapsto x=\sqrt{a}$

Now if a be 1,2,3,4....

$\\ \sf\longmapsto x=\sqrt{1}=1$

$\\ \sf\longmapsto x=\sqrt{2}$

$\\ \sf\longmapsto x=\sqrt{3}$

$\\ \sf\longmapsto x=\sqrt{4}=2$

And so on

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2 years ago

Will somebody please answer this question? I'm stuck and in a bit of a hurry. A surfboard shaper has to limit the cost of develo

ikadub [295]

Answer:

≥ 420 boards

Step-by-step explanation:

Write the required relation between cost per board and "x" (the number of boards that must be sold).

143 + 30240/x ≤ 215 . . . . . . . note that the first term is <em>not</em> 143x

Subtract 143

30240/x ≤ 72

Multiply by x/72. This is a positive number because x is a positive number.

30240/72 ≤ x

420 ≤ x

At least 420 surfboards must be sold to limit the final cost per board to $215.

8 0

3 years ago

Six less than a number is 15. Let x represent the number.

anygoal [31]

Answer: x - 6 = 15

Step-by-step explanation:

5 0

2 years ago

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Two coins are flipped how many outcomes are possible

grin007 [14]

Answer:

In an experiment of flipping two coins, there are four possible outcomes.

Step-by-step explanation:

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3 years ago

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An ecological group suspects tuna are consuming dangerous levels of copper in a region of the world. Dangerous levels of copper

Mademuasel [1]

Answer:

Step-by-step explanation:

A) From the stem-leaf plot, we see that out of 21 tunas, 5 have dangerous levels of copper since the levels go beyond 5.7 parts per million. The required proportion is 5/21=0.2381

B) Given the sample mean is {x}=4.77, sample standard deviation s=1.16 and the sample size is n=21.

Since the population standard deviation is not known, we use t-distribution.

So the 98% CI for mean is

4.77 ± t{1-0.02 /2,20} x 1.16/sqrt(21) = (4.13, 5.41)}

We are sure with 98% confidence the true copper level (in parts per million) lies in the interval (4.13, 5.41)

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2 years ago