well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)
![f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cbegin%7Bcases%7D%207x%2Bk%2C%26x%5Cleqslant%202%5C%5C%20kx%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%282%29%3D%20%5Cbegin%7Bcases%7D%207%282%29%2Bk%2C%26x%5Cleqslant%202%5C%5C%20k%282%29%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%207%282%29%2Bk~~%20%3D%20~~k%282%29%5E2-6%5Cimplies%2014%2Bk~~%20%3D%20~~4k-6%20%5C%5C%5C%5C%5C%5C%2014~~%20%3D%20~~3k-6%5Cimplies%2020~~%20%3D%20~~3k%5Cimplies%20%5Ccfrac%7B20%7D%7B3%7D%3Dk)
Answer:
99/hour
Step-by-step explanation:
7*85=585:6=99 ndjdjdjduxhskshuejsjs
Answer:
The graph is shifted 3 units to the left
Step-by-step explanation:
Answer:
0.9
Step-by-step explanation:
14/15 = 0.933333333 <u>IF:</u>
<u></u>
<u>1.</u><em> You first change it into a decimal by dividing the numerator by the denominator.</em>
<em> </em>14 ÷ 15
<u>2.</u> <em>You will get a recurring decimal.</em>
<em> </em>0.933333333
<u>3.</u><em> The first digit after the decimal is in the position of the '</em><u><em>tenths'</em></u>
0.<u>9</u>
<u>4.</u><em> You should use only two digits after the decimal to calculate </em>
<em> 0.93</em>
<u>5.</u><em> Since the number 3 is less than five, it will change into a zero and get eliminated.</em>
<em> ∴ The answer will be = 0.9</em>
Answer:
2x for the first term
The whole thing is 2x+3
Step-by-step explanation:
Think of it like normal division
What will get the closest answer to 2x^2+x?
2x*x-1=2x^2-2x
Now the expression is 3x-3 so if you but 3 than it becomes 3x-3 which would be a remainder of 0