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katrin [286]
3 years ago
5

A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.

Mathematics
2 answers:
klio [65]3 years ago
7 0
A) using f=ma, F=m1 x 3.00 =3m1
also F=m2 x 1.00 = m2
as the Fs are the same: 3m1=m2
this means that the ratio of m1 to m2 is 3 to 1 as there are 3 m1s for every m2.
b) again using f=ma, the combination of the masses is m1 + m2 or 4m1 as there are 3m1s in m2. so F=4m1 x a = 3m1 (as F is the same for all of them).
a = 3m1/4m1 = 3/4ms^-2
Lerok [7]3 years ago
6 0
A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3
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2 years ago
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n200080 [17]

Answer:

x = 7

y = 12

Step-by-step explanation:

To do this question you have to know your exponent rules, but also you need to know how to add fractions.

To multiply

6^(1/3) × 6^(1/4)

you can keep the 6 and just add the exponents.

That's why the answer is set up on the form 6^(x/y)

To add fractions, you need a common denominator, it is 12.

1/3 is 4/12.

1/4 is 3/12.

So 1/3 + 1/4

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4/12 + 3/12

= 7/12

7/12 is the exponent you are looking for.

x = 7 and y = 12.

6^(1/3) × 6^(1/4)

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2 years ago
Please help me, i promise its worth it!!!
Rashid [163]

\\ \sf\longmapsto 2(L+B)=55

\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55

\\ \sf\longmapsto \dfrac{8}{3}x+2x=55

\\ \sf\longmapsto \dfrac{8x+6x}{3}=55

\\ \sf\longmapsto \dfrac{14x}{3}=55

\\ \sf\longmapsto 14x=165

\\ \sf\longmapsto x=11.78

\\ \sf\longmapsto x\approx 12

Now

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Answer:

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Step-by-step explanation:

112 x 0.04 = 4.48

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