Question

A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.

Answer 1

A) using f=ma, F=m1 x 3.00 =3m1
also F=m2 x 1.00 = m2
as the Fs are the same: 3m1=m2
this means that the ratio of m1 to m2 is 3 to 1 as there are 3 m1s for every m2.
b) again using f=ma, the combination of the masses is m1 + m2 or 4m1 as there are 3m1s in m2. so F=4m1 x a = 3m1 (as F is the same for all of them).
a = 3m1/4m1 = 3/4ms^-2

Answer 2

A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3