Multiply the numbers
2(2/3)
2/1(2/3)= 4/3 = 1 1/3
If 81=n-3(-5+4n)
81= n+15-12n
81= -11n+15
-11n=81-15
-11n=66
n=-6
From the problem :
In multiplying expressions with the same bases, the exponent will be added accordingly.
For example :
the exponent of a are m and n, and the product will be a raised to the sum of m and n.
Applying this to the problem, we have :
The answer is d. 6^-1
Answer: IX - 4I ≤ 4
Step-by-step explanation:
In the numer line we can see that our possible values of x are in the range:
0 ≤ x ≤ 8
And we want to find an absolute value equation such that this set is the set of possible solutions.
An example can be:
IX - 4I ≤ 4
To construct this, we first find the midpoint M of our set, in this case is 4.
Then we write:
Ix - MI ≤ IMI
Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.
