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vazorg [7]
3 years ago
6

At a bargain store, Jen bought 4 items that each cost the same amount. Carol bought 5 items that each cost the same amount, but

each was $1.75 less than
the items that Jen bought. Both Jen and Carol paid the same amount of money. What was the individual cost of each person's items?
Mathematics
1 answer:
posledela3 years ago
8 0
Jens items cost-x
carol-x+y
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Factor out the greatest common factor. 10a3b−6a2b2
podryga [215]

Answer:

2a^2b(5a-3b)

If not then the other way is

5a-3b

Step-by-step explanation:

The GCF of 10a^3b and -6a^2b^2 is 2a^2b

So divide by that you will get

2a^2b(5a-3b)

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zmey [24]

Answer:

n=3

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Step-by-step explanation:

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If a 200 N net force acts on a 500 grams car, what will the acceleration of the car be? ​
ladessa [460]

Answer:

The acceleration of the car will be 400 m/s².

Step-by-step explanation:

The acceleration of the car can be found using Newton second law:

F = ma

Where:

F: is the net force = 200 N

m: is the mass = 500 g

a: is the acceleration =?

Then, the acceleration will be:

a = \frac{F}{m} = \frac{200 N}{500 g*\frac{1 kg}{1000 g}} = 400 m/s^{2}  

Therefore, the acceleration of the car will be 400 m/s².

I hope it helps you!

4 0
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1. Una escalera de 4 m de longitud se apoya sobre una pared vertical. Si la distancia entre la base de la escalera a la pared es
enot [183]

Answer:

puedes resolver de dos maneras si diste teorema de Pitágoras lo aplicas

hipotenusa al cuadrado = cateto 2 +cateto 2 ( el 2 significa al cuadrado)

sustituyes

hipotenusa= 4m

cateto= 2,5

hay que hallar el otro cateto que nos daría la altura a la que está la escalera

despejamos y tenemos

cateto 2= hip2 -cat2

cat2=(4)2-(2,5)2=

       =   16-6,25=9,75

luego hallamos la raíz cuadrada de 9,75= 3,12

     

la altura a la que se encuentra es 3,12m

-si aun no diste Pitágoras podes representarlo en una hoja utilizando cm en lugar de metros( a escala). trazas el triángulo rectángulo la base te la da la distancia a la cual se encuentra la escalera de la pared es decir 2,5cm trazas la hipotenusa de 4cm de manera que coincida con el cateto opuesto , y mides el valor de este ,será de 3,12cm no olvides que la respuesta la debes dar en metros ya que es la unidad de medida que te da.

4 0
3 years ago
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