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algol [13]
3 years ago
11

Can someone help me ASAP PLEASEE!

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

Area- (4x+3)(3x-1)

Area- (12x^2 + 9x-4x-3)

Area- (12x^2 +5x-3)

Area- 12x^2 + 5x - 3

Let  me know if this helps!

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The highest rated of the four European cities under consideration: This can be done by multiplying factor and importance and sum
arlik [135]

Answer:

The question is not complete, as the table containing the data is missing, but I found a matching table that can be used to answer the question.

The Question is:

Which is the highest rated, of the four European cities under consideration, using the table.

The correct answer is: City A is the highest rated European city.

Step-by-step explanation:

The highest rated European city can be found by multiplying the factor and the importance of the factors, and summing up their final values. the cty with the highest number is the one with the highest rated city. Having this in mind, let us calculate the ratings for each of the cities as follows:

City A:

(70 × 20) + (80 × 20) + (100 × 20) + (80 × 10) + (90 × 10) + (65 × 10) + (70 × 10) = 1400 + 1600 + 2000 + 800 + 900 + 650 + 700 = 8050

City B:

(70 × 20) + (60 × 20) + (50 × 20) + (90 × 10) + (60 × 10) + (75 × 10) + (60 × 10) = 1400 + 1200 + 1000 + 900 + 600 + 750 + 600 = 6450

City C:

(60 × 20) + (90 × 20) + (75 × 20) + (65 × 10) + (50 × 10) + (85 × 10) + (65 × 10) = 1200 + 1800 + 1500 + 650 + 500 + 850 + 650 = 7150

City D:

(90 × 20) + (75 × 20) + (90 × 20) + (65 × 10) + (70 × 10) + (70 × 10) + (80 × 10)   = 1800 + 1500 + 1800 + 650 + 700 + 700 + 800 =7950

Therefore, from the ratings computed above, City A with a rating of 8050, is the highest rated, while City B with a rating of 6450, is the lowest rated.

7 0
3 years ago
Tan(-x)csc(-x)/sec(-x)cot(-x) simplify the expression
svlad2 [7]

\bf \cfrac{tan(-x)csc(-x)}{sec(-x)cot(-x)}\implies \cfrac{\quad \frac{sin(-x)}{cos(-x)}\cdot \frac{1}{sin(-x)}\quad }{\frac{1}{cos(-x)}\cdot \frac{cos(-x)}{sin(-x)}}\implies \cfrac{\quad \frac{1}{cos(-x)}\quad }{\frac{1}{sin(-x)}} \\\\\\ \cfrac{1}{cos(-x)}\cdot \cfrac{sin(-x)}{1}\implies \cfrac{sin(-x)}{cos(-x)}\implies \cfrac{\stackrel{\stackrel{symmetry}{identities}}{-sin(x)}}{cos(x)}\implies -tan(x)

8 0
3 years ago
Please help!!! i will give brainliest
belka [17]
Susan has 50 so the difference is 5 sense sheila had 45
6 0
3 years ago
Read 2 more answers
WILL BE MARKED BRAINLIEST PLEASE HELP!!!!!!!!!
salantis [7]

Answer:

x_{3}=2

The first term is \frac{1}{2}

 

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=-2%283%20-%202x%29%20%3D%20-6x%20%2B%208%28x%20%2B%202%29" id="TexFormula1" title="-2(3 - 2x)
vovikov84 [41]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 11}}}}}

Step-by-step explanation:

\sf{ - 2(3 - 2x) =  - 6x + 8(x + 2)}

Distribute -2 through the parentheses

Similarly, Distribute 8 through the parentheses

\dashrightarrow{ \sf{ - 6 + 4x =  - 6x + 8x + 16}}

Collect like terms

\dashrightarrow{ \sf{ - 6 + 4x = 2x + 16}}

Move 2x to left hand side and change it's sign

Similarly, move 6 to right hand side and change it's sign

\dashrightarrow{ \sf{4x - 2x = 16 + 6}}

Collect like terms

\dashrightarrow{ \sf{2x = 16 + 6}}

Add the numbers : 16 and 6

\dashrightarrow{ \sf{2x = 22}}

Divide both sides by 2

\dashrightarrow{ \sf{ \frac{2x}{2}  =  \frac{22}{2} }}

Calculate

\dashrightarrow{ \sf{x = 11}}

Hope I helped!

Best regards! :D

5 0
3 years ago
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