Answer:
![\large\boxed{\sqrt{70}\approx8}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Csqrt%7B70%7D%5Capprox8%7D)
Step-by-step explanation:
![\text{We know:}\\\\\sqrt{a}=b\iff a^2=b,\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\5^2=25](https://tex.z-dn.net/?f=%5Ctext%7BWe%20know%3A%7D%5C%5C%5C%5C%5Csqrt%7Ba%7D%3Db%5Ciff%20a%5E2%3Db%2C%5C%20%5Ctext%7Bfor%7D%5C%20a%5Cgeq0%5C%20%5Cwedge%5C%20b%5Cgeq0%5C%5C%5C%5C5%5E2%3D25%3C70%5C%5C6%5E2%3D36%3C70%5C%5C7%5E2%3D49%3C70%5C%5C8%5E2%3D64%3C70%5C%5C9%5E2%3D81%3E70%5C%5C%5C%5C%5Ctext%7BTherefore%7D%5C%20%5Csqrt%7B64%7D%3C%5Csqrt%7B70%7D%3C%5Csqrt%7B81%7D%5CRightarrow8%3C%5Csqrt%7B70%7D%3C9.%5C%5C%5C%5C81-70%3D11%5C%5C70-64%3D6%5C%5C%5C%5C6%3C11%5C%5C%5C%5C%5Ctext%7BTherefore%7D%5C%20%5Csqrt%7B70%7D%5C%20%5Ctext%7Bis%20nearest%20to%7D%5C%20%5Csqrt%7B64%7D%3D8)
Step-by-step explanation:
5(tanx)^2 -2 +tanx=0
let tanx=y
5y^2 + y-2=0
y=0.5403 or y= -0.7403
tanx=0.5403
x=arctan(0.5403)
x=28.38°
or
tanx=-0.7403
x=arctan(-0.7403)
x=143.49°
(5•4)-8 the answer is 12 because 5 times 4 is 20. Then 20 minus 8 is 12.
I will solve your system by substitution.<span><span>x=<span>−2</span></span>;<span>y=<span><span><span>23</span>x</span>+3</span></span></span>Step: Solve<span>x=<span>−2</span></span>for x:Step: Substitute<span>−2</span>forxin<span><span>y=<span><span><span>23</span>x</span>+3</span></span>:</span><span>y=<span><span><span>23</span>x</span>+3</span></span><span>y=<span><span><span>23</span><span>(<span>−2</span>)</span></span>+3</span></span><span>y=<span>53</span></span>(Simplify both sides of the equation)
Answer:<span><span>x=<span>−<span><span>2<span> and </span></span>y</span></span></span>=<span>5/3
<span>
so the answer is B (the second choice)
(Hope it helped ^_^)
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Tan67=h/137
h=137tan67
h≈322.751 ft
h≈322.75 ft (to nearest hundredth of a foot)