Which of the following represents a geometric sequence?

Linear function need help ASAP

ElenaW [278]

Answer:

y=1/3x+2

Step-by-step explanation:

Because it is linear equation in 2 variables

4 0

3 years ago

Read 2 more answers

SUPER SIMPLE, Please help, I will mark brainliest

insens350 [35]

Easy it is clearly A

5 0

3 years ago

In the exponential growth function y = 235(1.15)^x, what is the

sweet-ann [11.9K]

Answer: Growth factor will be 0.15 and percent increase will be 15%.

Step-by-step explanation:

Since we have given that

the exponential growth function

$y=235(1.15)^x$

1) We need to find the growth factor :

As we know the formula for "Compound Interest ":

$A=P(1+\frac{r}{100})^x$

If we compare the formula with our given equation, we get

$1+\frac{r}{100}=1.15\\\\\frac{r}{100}=1.15-1\\\\\frac{r}{100}=0.15\\\\r=0.15\times 100\\\\r=15$

So, the growth factor is at the rate of 0.15.

2) Percent increase will be

$0.15=\frac{15}{100}\times 100\\\\=15\%$

Hence, growth factor will be 0.15 and percent increase will be 15%.

3 0

3 years ago

Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter

Otrada [13]

Part A:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that the lie detector will conclude that all 15 are telling the truth if all 15 applicants tell the truth is given by:

 $P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\ \\ =1\times0.0874\times1=0.0874$


Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

$P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\ \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\ \\ =0.9126$

Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

$\mu=npq \\ \\ =15\times0.15\times0.85 \\ \\ =1.9125$

Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The probability that the number of truthful applicants classified as liars is greater than the mean is given by:

 $P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\ \\ 1-[P(0)+P(1)]$

 $P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\ \\ =15\times0.15\times0.1028=0.2312$

8 0

3 years ago

Can u please help me please. Please

jonny [76]

The answer is
C = 4 ÷ 1/5

6 0

3 years ago