A-4=B
2+C=B
A+B+C=13
A=b+4
C=B-2
Plug in to equation 3
(B+4)+B+(B-2)=13
Rearrange
B=11/3
A=(11/3)+4= 23/3
C=(11/4)-2= 3/4
Answer:
log9
Step-by-step explanation:
hello :
note : a>0 and b>0
1) log(ab) = loga+logb
2) loga^n = nloga.....n in N
log(9x^5) + 5 log (1/x) = log(9x^5) + log (1/x)^5 = log((9x^5) (1/x)^5)
= log(9x^5)/(x^5)) = log9 because : (1/x)^5 = 1/x^5
Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
-2 + 5 = 3
Step-by-step explanation:
The arrow represents an addition, you start with -2 and add 5, so you end up at +3.
Answer:
x= 6/7z
Step-by-step explanation:
5x + 4z = 10z - 2x
5x + 2x = 10z - 4z
7x = 6z
x = 6/7z
