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3 years ago

Pls help‼️‼️‼️‼️ lol

Mathematics

1 answer:

timofeeve [1]3 years ago

7 0

Hello I’m back oof.

First chart: 3.14•2^
3.14•3^
3.14•4^
Second chart: 2(-4)-2
2(0)-2
2(4)-2
Third chart: 10(2^)+(1+1)
10(-1^)+(3+1)
10(-4^)+(4+1)

Hope this helps!

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3 years ago

2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

Answer:

x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

$\implies x = \frac{-3 \pm \sqrt{81}}{4}$

$\implies x = \frac{-3 \pm 9}{4}$

We get two values of 'x', viz.,

x = $\frac{-3 + 9}{4}$ and $\frac{- 3 - 9}{4}$

$\implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4}$

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $\frac{3}{2}$ ) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

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3 years ago

3a. The graph shows a school's profit P for selling x lunches on one day. PART A: What is the school's profit for selling 120 lu

konstantin123 [22]

Answer:

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Step-by-step explanation:

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3 years ago

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fredd [130]

Answer:

f(t) = 1.22·(173/122)^(t/5)

Step-by-step explanation:

(a) An exponential growth (or decay) function can be written using the form ...

f(t) = (initial value)·(ratio in period)^(t/period)

Here, we're given an initial value of 1.22, a growth ratio of 1.73/1.22 in a period of 5 years, so we can write the function as ...

f(t) = 1.22·(173/122)^(t/5)

(b) In 2038-2012 = 26 years, the value of the function is ...

f(26) = 1.22·(173/122)^(26/5) ≈ 7.50 . . . . million

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6+6
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3 years ago

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