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andriy [413]
3 years ago
5

What is the seventh term of a geometric sequence that has a common ratio of –3 and the first term is –4?

Mathematics
1 answer:
rjkz [21]3 years ago
4 0
An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916

I think this is right :)
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What is the missing angle for this or how do u do this pls add explanation!!!!!
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I think it's 360 degrees

Step-by-step explanation:

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3 years ago
Help plsssssss no links or files
marishachu [46]

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Step-by-step explanation:

5 0
3 years ago
For a polygon with 10 sides, which equation below represents the sum of the interior angles in the polygon?
jekas [21]

The sum of the interior angles in the polygon whose side is 10 is 1440^{0}

<h3>What is sum of interior angle of polygon ?</h3>

The sum of the interior angles in a regular polygon is given by the formula 180(n – 2), where n is the number of sides in the polygon.

As, The formula for calculating the sum of interior angles is ( n − 2 ) × 180^{0}

S0, n=10

Then, sum of interior angle be = (n-2) x 180

                                                   = (10-2) x 180

                                                   = 8 x 180

                                                   = 1440^{0}

Thus, the sum of the interior angles in the polygon is 1440^{0}

Learn more sum of interior angle of polygon here:

brainly.com/question/22408868?

#SPJ1

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
Where each input has only one output value is called a(n)
omeli [17]

C. Function

Hope this helps.

r3t40

8 0
3 years ago
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