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3 years ago

How to solve the problem?

Mathematics

1 answer:

Whitepunk [10]3 years ago

8 0

We would first have to combine like terms to solve for x
So 15x-2 and 5x+3 becomes 20x+1
This is the whole length of the segment, so 20x+1=5
We'll then solve for x by adding one to each side, this isolates x and the equation becomes 20x=6
We can then divide each side by 20 to get x alone
6/20=.3
So x=.3

Next we'll plug .3 into the equation as x
15(.3)-2=2.5
5(.3)+3=4.5

The midpoint divides the line into two equal pieces, and 2.5 does not equal 4.5 so Q is not the midpoint of the segment.

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Suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120°. What is the length of

dezoksy [38]

Answer:

A. 58.04°

Step-by-step explanation:

Let the sides of the triangle be A , B and C.

A = 32

B = 35

C = what we don't know.

The opposite angle to C is 120° and its just denoted as ∡C

The formula to find C² = A² + B² - 2ABcos∡C

C² = 32² + 35² - 2(32)(35)cos120°

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C² = 3369

C = $\sqrt{3369}$ ≅ 58.04°

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Answer:

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pshichka [43]

Check the picture below.

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$\bf h=64t-32t^2\implies h=-32t^2+64t+0 \\\\[-0.35em] ~\dotfill$

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-32}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{64}{2(-32)}~~,~~0-\cfrac{64^2}{4(-32)} \right)\implies \left( \stackrel{\stackrel{\textit{how many}}{\textit{seconds}}}{1}~~,~~\stackrel{\stackrel{\textit{how many feet}}{\textit{it went up}}}{32} \right)$

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