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adell [148]
2 years ago
13

A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordere

d pair (4, 3) is on the graphed line.
ASAP. 100 POINTS


Part A: What is the price of 1 pound of potatoes? Show your work. (8 points)
Part B: What does the ordered pair (8, 6) on the graph represent? Explain in words. (2 points)
Mathematics
2 answers:
goblinko [34]2 years ago
8 0
Answer:

part A is 0.75 pounds

Explanation:

i only know part A sorry but u will try and figure out part B
sergeinik [125]2 years ago
5 0

Answer:

Part A: The price for one pound is 0.75.

Part B: The ordered pair (8, 6) on the graph represents the pound of potatoes and the price for 2.

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Answer:

1) The mean calculated for this case is \bar X=61.5

2)  61.5-5.4=56.1

3) 61.5+5.4=66.9

4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part 1

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (a)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (b)  

The mean calculated for this case is \bar X=61.5

The sample deviation calculated s=5.143

\mu population mean (variable of interest)

n=6 represent the sample size  

Part 2

The confidence interval for the mean is given by the following formula:

\bar X \pm ME   (1)

So if we have the margin of error 5.4mm we can find the lowr limit like this:

61.5-5.4=56.1

Part 3

61.5+5.4=66.9

Part 4

B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.

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Answer:

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Answer:

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Step-by-step explanation:

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