Answer:
Step-by-step explanation:
The given rectangle has diagonals have the endpoints P(-3, -2) ,I(4, -7) and A(4, -2) ,D(-3, -7)
The diagonals of the rectangle bisect each other so we use the midpoint formula to find their point of intersection.
The midpoint formula is;
We use any pair of endpoints of the diagonals to find the point of intersection.
Using A(4, -2) ,D(-3, -7)
or
The number of ways when the choice is not relevant is 4
<h3>How to determine the number of ways?</h3>
The number of colors are:
Colors, n = 4
The color to choose are:
r = 3
<u>Relevant choice</u>
When the choice is relevant, we have:
This gives
Evaluate
Ways = 24
Hence, the number of ways when the choice is relevant is 24
<u>Not relevant choice</u>
When the choice is not relevant, we have:
This gives
Evaluate
Ways = 4
Hence, the number of ways when the choice is not relevant is 4
Read more about combination at:
brainly.com/question/11732255
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So you have to find something that multiples to six but also somehow either subtracts or adds to five. So I would pick 2 and 3 because two plus three is five. Then you would write out your equation
X2+2x+5x+6
This may not be the way your teacher taught however it is much easier for me to do it this way.
Answer:
C) Reflection about the origin
Step-by-step explanation:
DE points to the right and slightly down. D'E' points to the left and slightly up. The segments are parallel, not perpendicular, so represent a rotation of 180°, not 90°. If the figure were subject only to translation, these segments would point in the same direction.
The transformation is a reflection about the origin (C). (This is equivalent to a rotation of 180°.)
Solution:
A function is always a relation but a relation is not always a fucntion.
For example
we can make a realtion of student roll number and their marks obtained in mathematics.
So we can have pairs like (a,b), (c,d)..etc.
Its a realtion but it may not be function. Because function follows that for same input there should not be diffrent output, aslo there could be many inputs to one output in the case of constant function . But this doesn't holds a necessary condition in case of relation.
Because two diffrent students with two diffrent Roll number may have same marks.
Hence the foolowing options holds True in case of a function.
A) many inputs to many outputs or one input to one output.
D) one input to one output or many inputs to one output.
