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Llana [10]
3 years ago
5

a machine can produce 6 yards of fabric in 2 minutes. how much fabric can the machine produce in 1 hour

Mathematics
2 answers:
bagirrra123 [75]3 years ago
4 0

Answer:

180 yards of fabric can be produced in an hour.

Step-by-step explanation:

Step 1: Calculate how man yards of fabric the machine can produce in 1 minute.

6 yards of fabric per 2 minutes = 3 yards of fabric per 1 minute

Step 2: Calculate how much fabric the machine can produce in 1 hour.

3 yards of fabric * 60 minutes = 180 yards of fabric

GaryK [48]3 years ago
3 0

Multiply 6 by 60 then divide by two which will get you 180.

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116,160

Step-by-step explanation:

22 times 5,280= 116,160

There's 5,280 feet in a mile

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3 years ago
How do you show work for<br> 3(2)(-5)^3
Trava [24]

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You just put lines like how they do when showing distributive property...and write out 5x5x5

Step-by-step explanation:

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3 years ago
Alana bought a stock, which dropped 10% from the previous day. The value of her stock, after the price drop was $305 Wh ch equat
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If the original price was 'p', the new price would be 'p - 10%p' or 'p - 0.1p'. We know this is equal to 305, so 'p - 0.1 p = 305' would be the equation.
7 0
3 years ago
What is an equation of the line that passes through the points (-1, 6) and<br> (-1,-5)?
belka [17]

Answer:

x = -1    

Step-by-step explanation:

1) First, find the slope of the line by using the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(-5)-(6)}{(-1)-(-1)} \\m = \frac{-5-6}{-1+1}\\m =\frac{-11}{0}

The result we got was -\frac{11}{0}, but we can't divide by zero. This means that the slope of the line must be undefined instead.

2) All vertical lines have a slope that is undefined. So, this line must be vertical.

All vertical lines are represented by the equation x = a single number. That number represents the x-value of all the points the vertical line intersects. So, take the x-value of the given points (in this case, -1) and put it into that equation. So, the equation of the line must be x = -1.  

8 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
olga nikolaevna [1]

Answer:

maximum value , f max = 169 (taking the most out of the 4th power)

minimum value , f min = 169/3 (taking the least out of the 4th power)

Step-by-step explanation:

A) Since both function and restriction are symmetrical with respect to x,y and z, there is no reason for one to be more important than the others and therefore one solution would be x=y=z=λ and thus

x2 + y2 + z2 = 13  → 3λ² = 13 →λ² = 13/3

and f would be

f (x, y, z) = x4 + y4 + z4 = 3λ⁴ = 3*(13/3)²=13²/3=169/3

since x⁴ increases faster than 3*x² , f(x,y,z) would be a minimum

and the maximum value would be obtained taking the most out of x⁴, thus doing 2 coordinates =0 ( can be x=0 and y=0) and

z²= 13

f (x, y, z) = x4 + y4 + z4 = 13² = 169

B) strictly, using Lagrange multipliers

f (x, y, z) = x4 + y4 + z4

g (x, y, z) = x2 + y2 + z2 - 13

F(x,y,z) = f (x, y, z) -λ*g (x, y, z)

such that

Fx (x,y,z)=  fx(x, y, z) -λ*gx (x, y, z) = 0 → 4*x³ - λ*2*x = 0 → 2*x*(2*x² -λ) = 0

thus x=0 or x²= λ/2

Fy (x,y,z)=  fy(x, y, z) -λ*gy (x, y, z)= 0 → 4*y³ - λ*2*y = 0 → 2*y*(2*y² - λ) = 0

thus y=0 or y²= λ/2

Fz (x,y,z)=  fz(x, y, z) -λ*gz (x, y, z)= 0 → 4*z³ - λ*2*z = 0→ 2*z*(2*z² - λ) = 0

thus z=0 or z²= λ/2

g (x, y, z) = 0  → x2 + y2 + z2 = 13 → 3*(λ/2) = 13 → λ=13*2/3

thus  x²=y²=z²= λ/2 =13/3

f min = f (x, y, z) = x4 + y4 + z4 = 3*(13/3)²=169/3

for the x=0 , y=0 → z²= 13

f max = f (x, y, z) = x4 + y4 + z4 = 13² = 169

3 0
3 years ago
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