How can you tell whether an ordered pair is a solution of a linear inequality?

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

7 0

Hello from MrBillDoesMath!

Answer:

Suppose the ordered pair is (x.y). Substitute these values in the linear equality to see if it is true,

Example. Consider the point (7, -4). Is it a solution of the linear inequality

3x < 4y - 9? Let's check to find out.

Check:

Is 3 (7) < 4 (-4) - 9 true ?

Is 21 < -16 -9 = -25 ??

NO!

So (7,-4) is NOT a solution of the linear inequality.

Thank you,

MrB

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Please Help me. Also if you could show your work thatd be great.

Over [174]

Answer:

3) $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing)

4) $- \infty < y < 0$ or $( - \infty ,0)$ (same thing)

5) $-2$ or $(0, -2)$ (same thing)

Step-by-step explanation:

3) Domain represents the amount of $x$ -values in a function. The image shows that the function's arrows point in both directions (right and left), infinitely, so the domain would be $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing).

4) Range represents the amount of $y$ -values in a function. The function goes downward forever ( $- \infty < y$ ) by the indication of an arrow and halts just under the y-axis ( $y < 0$ ). After combining these two inequalities, you see that the range is $- \infty < y < 0$ or $( - \infty ,0)$ (same thing).