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Alexxx [7]
3 years ago
10

The sequence {an } is defined by a of o = 1 and a of n + 1 = 2 a of n + 2 for n = 0, 1, 2.... What is the value of a of 3?

Mathematics
1 answer:
maria [59]3 years ago
3 0
\begin{cases}a(0)=1\\a(n+1)=2a(n)+2&\text{for }n\ge0\end{cases}

Use the second part of the definition (the recursive one):


a(1)=2a(0)+2=4
a(2)=2a(1)+2=10
a(3)=2a(2)+2=22
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Trey evaluated 12/15 + 1/10 and got the answer of 13/25. which statement is true about this answer?
Ganezh [65]

Answer:

Option C. His answer is not correct, because the same can not be less than either attend

Step-by-step explanation:

we have

\frac{12}{15}+\frac{1}{10} =\frac{13}{25}

we know that

\frac{12}{15}=0.8

\frac{1}{10}=0.10

\frac{13}{25}=0.52

substitute

0.80+0.10=0.52 ----> is not true

therefore

His answer is not correct, because the same can not be less than either attend

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Kisachek [45]

Answer:

65ft

Step-by-step explanation:


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How many roots does this has?<br>x^2+(2√5x)+2x=-10​<br>find Discriminant
Alexxandr [17]

Given:

The equation is

x^2+(2\sqrt{5})+2x=-10

To find:

The number of roots and discriminant of the given equation.

Solution:

We have,

x^2+(2\sqrt{5})x+2x=-10

The highest degree of given equation is 2. So, the number of roots is also 2.

It can be written as

x^2+(2\sqrt{5}+2)x+10=0

Here, a=1, b=(2\sqrt{5}+2), c=10.

Discriminant of the given equation is

D=b^2-4ac

D=(2\sqrt{5}+2)^2-4(1)(10)

D=20+8\sqrt{5}+4-40

D=8\sqrt{5}-16

D\approx 1.89>0

Since discriminant is 8\sqrt{5}-16\approx 1.89, which is greater than 0, therefore, the given equation has two distinct real roots.

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3 years ago
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