Help with a domain questio please

0.6×8 and tell me how you got the answer pls<br><img src="https://tex.z-dn.net/?f=0.6%20%5Ctimes%208" id="TexFormula1" title="0.

Tresset [83]

Answer:

4.8 is the answer!

Step-by-step explanation:

0.6 x 8 = 4.8

6 x 8 = 48

multiply 6 by 8, and move the decimal to the left one time, and get 4.8

7 0

2 years ago

Read 2 more answers

what is 12/3 as an improper fraction? a. 2/3 b. 5/3 c. 8/3 d. 6/3 user: what is 20 × 6? a. 100 b. 40 c. 12 d. 120

Sedbober [7]

$1\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\boxed{\dfrac{5}{3}}\to\fbox{b.}\\\\20\times6=6\cdot(2\cdot10)=6\cdot2\cdot10=12\cdot10=\boxed{120}\to\fbox{d.}$

7 0

3 years ago

Pls help me. i need it

Juli2301 [7.4K]

Answer:

option 2 is correct

Step-by-step explanation:

5 0

3 years ago

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0

3 years ago

A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2

Yanka [14]

Answer:

$-60\frac{3}{4}$ meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract $10\frac{1}{2}$ from $-50\frac{1}{4}$ because diver dives away another $10\frac{1}{2}$ from his previous location of $-50\frac{1}{4}$ .