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FrozenT [24]
3 years ago
6

Brainliest being offered for the RIGHT answer.

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0
<span> Start with the given equation 


 Subtract 6 from both sides. 


 Combine like terms. 


Now let's graph  </span>
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What is 2/28=7/8 cross multiplied
siniylev [52]

Answer:

see the explanation

Step-by-step explanation:

we have

\frac{2}{28}=\frac{7}{8}

we know that

To cross multiply, start by multiplying the numerator of the left-hand fraction by the denominator of the right-hand fraction.

2(8)

Then, multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.

7(28)

Next, set the 2 products equal to each other.

2(8)=7(28)

5 0
3 years ago
How to prove its congruent
Katen [24]
There are five ways to find if two triangles are congruent: SSS, SAS, ASA, AAS and HL.<span>SSS (side, side, side) SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. ... SAS (side, angle, side) ... ASA (angle, side, angle) ... AAS (angle, angle, side) ... <span>HL (hypotenuse, leg)
</span></span>
8 0
2 years ago
12(x-2) + 3x = 1/2(x + 6) + 2
Verizon [17]

Answer:

x=2

Step-by-step explanation:

8 0
3 years ago
What is 209 divided by 34? Put your answer in fraction form, Simplify.
klasskru [66]
209 divided by 34 is 6.14
this is 6 14/100   simplified is 6 7/50
4 0
2 years ago
Andrew's math teacher entered the seventh grade students in a math competition there was an enrollment fee of $30 and also an $1
N76 [4]

Answer: 110

Step-by-step explanation:

Given;

Total cost C = $151

Enrollment fee E = $30

Charge per 10 test t = $11

n is the number of packet of test taken.

The questions can be represented by the equation below;

30 + 11n = 151

Substracting 30 from both sides.

11n = 151-30 = 121

n = 121/11

n = 11

Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;

N = 10 n = 10 ×11 = 110

N = 110

5 0
3 years ago
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