Y - x - 3 = 0
y = x + 3
y = x^2 - x - 12
x + 3 = x^2 - x - 12
x^2 - x - 12 - x - 3 = 0
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x - 5 = 0 y = x + 3
x = 5 y = 5 + 3
y = 8
x + 3 = 0 y = x + 3
x = -3 y = -3 + 3
y = 0
so ur solutions are : (5,8) and (-3,0)
Answer:
33% chance
Step-by-step explanation:
there are 12 students total and there are two groups of students, boys and girls, 8 girls 4 boys so we take that and convert it to a fraction which would make 2/3 girls and 1/3 boys, so that would mean that boys have a 33% chance of being selected
<u>Answer:</u>
<h2><u>-2.25</u></h2><h3>
<u>Step-by-step explanation:</u></h3>
Lets start with D:
It says, 0.43 but we're on the OPPOSITE of 0, so it can't be a positive number.
Same goes for C.
Now we are on to our last two.
B, is -2.5 and A, is -0.8
So, now we look at the point <em>B </em>and <em>assume</em>, because it says Select a reasonable value for Point B.
To me, point <em>B </em>looks to be about around -2.0
So, the <em>reasonable value </em>for this problem would be -2.25
since its over 1 it just makes it 24
8/10 is the answer to this problem
