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vesna_86 [32]
3 years ago
13

There were 6 seventh graders on a middle school wrestling team. The

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

-6 negative six

Step-by-step explanation:

3- 2 - 1 - 4 + 2 - 4= -6

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molly has alot of skirts she categorizes them as either "casular or "trendy" skirts. Molly has 8 "casual" skirts. if ger "trendy
lesya [120]

She owns 20 skirts in total.

6 0
3 years ago
Which of these intervals has an average rate of change that is less than 1/4
RideAnS [48]

Answer:

Interval [b,c] and interval [c,d]

Step-by-step explanation:

a(-5,0)

b(-1,2)

c(4,3)

d(11,4)

The average rate of change is the the total rise over the total run.

The Rise means the vertical increase and the Run means horizontal incease.

For interval [a,b]

rate of change is \dfrac{2-0}{-1-(-5)}=\dfrac{2}{4}=\dfrac{1}{2}

For [b,c]

\frac{3-2}{4-(-1)}=\frac{1}{5}

For [c,d]

\dfrac{4-3}{11-4}=\dfrac{1}{7}

8 0
2 years ago
The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.
ololo11 [35]

Answer: (a)  {a, ar, ar², ar³, ar⁴, ar⁵...}, (b)  arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.  

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0
3 years ago
. Зn – 1 = 8<br> Pls tell me what n equals lol
Naddika [18.5K]

Answer:

Зn – 1 = 8

3n=9

n=3

Hope This Helps!!!

8 0
3 years ago
Read 2 more answers
I need to find sec(theta)= 2(sqrt3)/3
Sloan [31]

Answer: 30° and 330°

<u>Step-by-step explanation:</u>

sec θ = \frac{2\sqrt{3}}{3}

sec θ = \frac{1}{cos(\theta)}

\frac{1}{cos(\theta)} = \frac{2\sqrt{3}}{3}

cos θ = \frac{3}{2\sqrt{3}}

cos θ = \frac{3}{2\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}})

cos θ = \frac{3\sqrt{3}}{3*2}

cos θ = \frac{\sqrt{3}}{2}

Look at the Unit Circle to see that cos = \frac{\sqrt{3}}{2} at 30° and 330°  ( which is equivalent to π/6 and 11π/6)


4 0
3 years ago
Read 2 more answers
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