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Basile [38]
3 years ago
9

If a woman has 10 gene pairs, how many genetically different eggs can be formed if three of the gene pairs are homozygous and th

e remaining seven gene pairs are heterozygous?
a.128
b.256
c.512
d.1024
Biology
1 answer:
Gelneren [198K]3 years ago
4 0

gene pairs - AABBCCDdEeFfGgHhIiJj

number of possible types of eggs - 1*2*2*2*2*2*2*2=128

reply "a" is good

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the couple is also concerned about their child inheriting hemophilia, another rare disease, which is x-linked. natalie’s brother
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Hemophilia is a recessive X-linked condition and is inherited from parents. . The probability that Natalie and Daniel’s first child has hemophilia is<u> 1/4</u>, not 1/8. The statement is<u> false.</u>

<h3>What is an X-linked gene?</h3>

When talking about sex-linked genes, we refer to all those genes located in one of the sex-chromosomes and not in the somatic ones.

X-linked genes are the genes located specifically in the X sex chromosome.

Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations.

According to this, X-linked genetic disorders will be inherited as well.

  • Men have a high probability of being affected since they only have one copy of the X chromosome.
  • In women, the effect of the mutation might be musk in heterozygous state if the mutation is recessive.

Hemophilia is a recessive X-linked disorder, which means it is coded by the recessive allele.

  • X+ ⇒ X chrosomosome with Dominant allele
  • X- ⇒ X chrosomosome with Recessive allele

<u>Genotype              Phenotype</u>

X+X+                   Healthy woman

X+X-                    Healthy carrier woman

X-X-                     Hemophilic woman

X+Y                      Healthy man

X-Y                       Hemophilic man

Let us make a pedigree of these families,

<u>Natalie's family</u>:

Mother         healthy carrier          X+X-

Father          healthy                      X+Y

Brother        hemophilic                X-Y  

Natalie         Healthy                     X+X- or X+X+  

Natalie has 1/2 chances of being carrier X+X- and 1/2 of being X+X+.

<u>Daniel's family</u>:

Mother         healthy carrier          X+X-

Father          hemophilic                X-Y  

Sister           hemophilic                X-X-

Daniel          Healthy                      X+Y

He has 1/2 chances of being healthy X+Y and 1/2 of being affected X-Y.

According to the product probability rule, if events A and B are independent from each other, the probability of occurrence of both events together is

P(A∩B) = P(A) x P(B)

In this case,

  • event A is Daniel being affected ⇒ 1/2
  • event B is Natalie being carrier ⇒ 1/2

P(A∩B) = P(A) x P(B) = 1/2 x 1/2 = 1/4

The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is<u> false.</u>

You can learn more about X-linked genes at

brainly.com/question/12420228

brainly.com/question/14704182

brainly.com/question/1387724

#SPJ1

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