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Rasek [7]
3 years ago
5

In what instance would you use the upside down U when doing interval notation

Mathematics
1 answer:
Jet001 [13]3 years ago
8 0
The U and inverted U symbols, ∪ and ∩, are mathematical symbols used to denote union or intersection, respectively. For example, when a rational algebraic equation is graphed, there may be some points where the equation is undefined. Visually, we see it as breaks or discontinuities. We use the ∪ symbol to express union. For example, {-∞,2)∪(4,+∞). That means that the graph passes at all x values except x=3.

The ∩ symbol is used for intersection of two lines, for instance. When equation A and equation B are graphed, they can intersect at points (x,y). It is therefore expressed as: A∩B = (x,y).
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umka2103 [35]

Answer:

x= 99

Step-by-step explanation:

first we open brackets

6x+36=7x-63

transpose

6x-7x= -63-36

-x=-99

the signs cancel each other so

x= 99

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Cheri walked 12 blocks in 36 minutes. What was Cheri's speed per minute?
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brian and shawna are selling cookie dough. ryan sold 6 packod cookie dough and 12 packages of gingerbread cookies dough for a to
Bogdan [553]

Answer:

Chocolate chip dough = $12

Gingerbread cookie dough = $17

Step-by-step explanation:

Since there are two variables in this problem, setting up a system of equations and using the elimination method will help us find the cost for each package of cookie dough.  Based on Ryan's sales of 6 packages of chocolate chip and 12 packages of gingerbread for $276, the first equation is:

6c + 12g = 276

Since Shawna sold 8 chocolate chip and 3 gingerbread for a total of $147.00, the second equation is:

8c + 3g = 147

Using the elimination method, we will need to multiply the second equation by a factor of -4 in order to eliminate the variable 'g':

-4(8c + 3g = 147) = -32c - 12g = -588

Add the two equations:

6c + 12g = 276

+ <u> -32c - 12g = -588</u>

-26c = -312  or c = $12

Plug the value of 'c' into the first equation:

6(12) + 12g = 276 or 72 + 12g = 276 or g = $17

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3 years ago
4. Trina will add fringe along the edges of
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