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cluponka [151]
3 years ago
9

A furniture company is producing three types of furniture. Product A requires 7 board feet of wood and 4 lbs of wicker. Product

B requires 5 board feet of wood and 5 lbs of wicker. Product C requires 4 board feet of wood and 3 lbs of wicker. There are 3000 board feet of wood available for product and 1400 lbs of wicker. Product A earns a profit margin of $35 a unit, Product B earns a profit margin of $42 a unit, and Product C earns a profit margin of $20 a unit. Formulate the problem as a linear program.
Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0

Step-by-step explanation:

this is a linear programming problem, and we are expected to draw up the linear program for the solution of the problem.

The objective function is

Maximize

35A+42B+20C=P    

subject to constraints(board and wicker)

The constraints are

  board

7A+5B+4C=3000

 wicker

4A+5B+3C=1400

A>0, B>0, C>0

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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y
Lilit [14]
No he's not correct

<span>(3 – 6y2)(y2 + 2)  
= 3(y2) -6(y2)(y2)  - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
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3 0
3 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
What is the answer to <br>3p-5&gt;2p+p-7
svet-max [94.6K]

Step-by-step explanation:

3p−5>2p+p−7

3p−5>3p−7

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0>−2

Answer:

All real numbers are solutions.

-sammy

Hope this helps u mark me as brainiest if u think its right

3 0
3 years ago
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zheka24 [161]
That "9 minutes" doesn't affect the outcome!

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