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alukav5142 [94]
3 years ago
6

June made a design with 6 equal tiles. One tile is yellow, 2 tiles are blue, and 3 tiles are purple. What fraction of the tiles

are yellow or purple
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer: \frac{2}{3}

<u>Step-by-step explanation:</u>

yellow      or       purple

    \frac{1}{6}          +           \frac{3}{6}

=               \frac{4}{6}

=               \frac{2}{3}

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Can i get some help please??? Thanks!!!!
Varvara68 [4.7K]

Answer:

9.6

Step-by-step explanation:

d =  \sqrt{ {8}^{2}  +  {2}^{2} +  {5}^{2}  }  \\  =  \sqrt{64 + 4 + 25}  \\  =  \sqrt{93}  \\  = 9.64365076 \\  = 9.6

8 0
3 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
During two years, the population of birds of an island became 7 times more than before. If the first year increase in the popula
nordsb [41]

Answer:

The percent increase of the second year is 400%.

Step-by-step explanation:

Consider the provided information.

Let the population of birds was x.

After 2 years the population becomes 7 times more than before.

Therefore, after 2 years population is 7x.

In first year increase in the population was 40%.

Population after 1st year = x + 40% of x

Population after 1st year = x + 0.40x

Population after 1st year = 1.4x

The population increase from 1st year to 2nd year is: 7x-1.4x=5.6x

Thus the percentage increase is:

\% increase=\frac{5.6x}{1.4x}\times100=400\%

Hence, in second year the population of birds increase by 400%.

6 0
3 years ago
What is the derivative of cosx
grandymaker [24]
-sinx + C
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A man awoke to a temperature of 40 °F.By the time he arrived at work,the temperature had increased by 11°F.At lunch ,the tempera
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The tenperature when he arrived home was 26
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