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ipn [44]
3 years ago
11

Ava,Carter,Luke and their dad each mow a different section of their yard.Ava mow 1 /12 of the yard, Carter mow 2 /12 of the yard

,and Luke mows 4/12 of the yard.Their dad mows the rest of the yard.How much did his dad now
Mathematics
2 answers:
DanielleElmas [232]3 years ago
7 0
Since Ava mowed 1/12, Carter mowed 2/12, and Luke mowed 4/12 add that together and that equals 7/12. Subtract 7 from 12 and that equals 5. So therefore the dad mowed 5/12.
lubasha [3.4K]3 years ago
4 0
His dad mowed 5/12 of the yard
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Mean Absolute Deviation (MAD): 1.6
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Two angles are complementary. The measure of one angle is 6º more than five times the measure of the other angle. Find the
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Complementary means that the two angles sum to 90 degrees.

So based on the problem, let:

1st angle=5x+6

2nd angle=x

Now create an equation.

x+5x+6=90

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x=14

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3 years ago
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A study was conducted to determine if the salaries of elementary school teachers from two neighboring districts were equal. A sa
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Answer:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

(–2975, 175)

Do not reject H₀

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Z_{1-\alpha /2} = Z_{0,975} = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values ​​differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

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