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Tanzania [10]
3 years ago
9

In a city, the distance between the Liebrary in the police station is 3 miles less than twice the distance between the police st

ation in the fire station. The distance between the Library and a police station is 5 miles. How far apart are the police station and the fire station?
Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

4

Step-by-step explanation:

l->p=5

p->f (5+3)/2=4

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Find the length of QP given Q is the midpoint of XF, PQ =2X+1, XF=7X-4, PF=X
nadezda [96]

Answer:

Therefore the length of QP = 3.4 units

Step-by-step explanation:

Given:

PQ = 2x + 1

XF = 7x - 4

PF = x

Q is the mid poimt of XF

∴ XQ = QF

QF = PQ - PF  ..........( Q - F - P )

     = 2x + 1 - x

∴ QF      = x + 1

∴ XQ = QF = x + 1

TO Find:

QP = ?

Solution:

By Addition Property we have

XP = XQ + QF+PF ..........(X-Q-F-P)\\\\

XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\

Substituting the given values in above equation we get

(7x - 4) + x = (x +1) + (x +1) + x

8x -4 = 3x +2

8x - 3x + 4 + 2

5x = 6

∴ x = \frac{6}{5}

Now we require

QP = (2x + 1)

∴ QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit

Therefore the length of QP = 3.4 units

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3 years ago
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Answer:

Step-by-step explanation:

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4 0
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g The weight of a certain type of apple is normally distributed with a mean of 10.56 ounces and standard deviation of 0.9 ounces
jeyben [28]

Answer:

First Quartile Q1 = 9.9525

Step-by-step explanation:

For a standard normal distribution,

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From the question mean μ = 10.56

Standard deviation σ = 0.9

Plugging these values into the first quartile equation, we have;

Q1 = 10.56 -0.675(0.9)

Q1 = 10.56 - 0.6075

Q1 = 9.9525

6 0
3 years ago
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