Answer:
4.333 meters
Step-by-step explanation:
Given:
We are told that the rope is cut into two pieces and that one (longer) piece is twice the length of the other (short) piece
let the length of the short piece = x meters
hence the length of the longer piece = 2x meters
we are also given that the total length of the two pieces is 6.5m
hence,
length of short piece + length of long piece = 6.5 m
in equation form:
x + 2x = 6.5
3x = 6.5 (divide both sides by 3)
x = 6.5/3 meters
we are asked to find the length of the long piece (i.e 2x)
hence
2x = 2 (6.5/3) = 4.333 meters (answer)
Answer:
Step-by-step explanation:
![3\log_5(x-10)-\dfrac{1}{2}\log_54=5\log_52\\\\\text{Domain:}\ x-10>0\to x>10\\\\\text{use}\\\\\log_ab^n=n\log_ab\\\\\log_ab-\log_ac=\log_a\left(\dfrac{b}{c}\right)\\========================\\\\\log_5(x-10)^3-\log_54^\frac{1}{2}=\log_52^5\qquad\text{use}\ a^\frac{1}{2}=\sqrt{a}\\\\\log_5(x-10)^3-\log_5\sqrt4=\log_532\\\\\log_5(x-10)^3-\log_52=\log_532\\\\\log_5\dfrac{(x-10)^3}{2}=\log_532\iff\dfrac{(x-10)^3}{2}=32\qquad\text{multiply both sides by 2}\\\\(x-10)^3=64\to x-10=\sqrt[3]{64}\\\\x-10=4\qquad\text{add 10 to both sides}\\\\x=14\in D](https://tex.z-dn.net/?f=3%5Clog_5%28x-10%29-%5Cdfrac%7B1%7D%7B2%7D%5Clog_54%3D5%5Clog_52%5C%5C%5C%5C%5Ctext%7BDomain%3A%7D%5C%20x-10%3E0%5Cto%20x%3E10%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%5C%5C%5C%5Clog_ab%5En%3Dn%5Clog_ab%5C%5C%5C%5C%5Clog_ab-%5Clog_ac%3D%5Clog_a%5Cleft%28%5Cdfrac%7Bb%7D%7Bc%7D%5Cright%29%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_54%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Clog_52%5E5%5Cqquad%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%7Ba%7D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_5%5Csqrt4%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_52%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D%5Clog_532%5Ciff%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D32%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%202%7D%5C%5C%5C%5C%28x-10%29%5E3%3D64%5Cto%20x-10%3D%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5Cx-10%3D4%5Cqquad%5Ctext%7Badd%2010%20to%20both%20sides%7D%5C%5C%5C%5Cx%3D14%5Cin%20D)
Answer:
First, we know that the area of a rectangle of width W and length L is:
A = W*L
In the case of Roberto's plan, we can see that the length of the whole rectangle is:
L = 1.5ft + x + 1.5ft = 3 ft + x
And the width is:
W = 3ft + x + 3ft = 6ft + x
Then the area of the whole thing is:
A = (3ft + x)*(6ft + x)
This is what we wanted, a product of two polynomials that represents the area of Roberto's plot.
Now if we subtract the white square (is a square of sidelength x, then its area is A = x*x) we will get the area of the border;
The total area of Roberto's borders is:
Area of the border = (3ft + x)*(6ft + x) - x*x
= 3ft*6ft + 3ft*x + x*6ft + x^2 - x^2
= x*9ft + 18ft^2
When 0 < a < 1, the amplitude of the graph decreases, causing the slopes of the graph to appear more "flat".
Answer:
2.5
Step-by-step explanation:
It looks like it's 2.5.
