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3 years ago

Which could be the mensures of three angles of an acute triangle

Mathematics

1 answer:

jek_recluse [69]3 years ago

5 0

Answer: Answer B is correct

Step-by-step explanation:

Answer B is correct because an acute triangle consists of 3 angles that are less than 90 degrees, and their sum is 180 degrees.

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5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$

5 0

3 years ago

There are five tests in a grading period. A student received grades of 98, 80, and 90, 96 on the first four tests. What grade mu

inn [45]

Answer:

Step-by-step explanation:

The median of the group is 80

If you add all the five numbers up they equal 454 divide by 5 the answer would be 90.8

3 0

3 years ago

Givien h(x) = -x- 5, find h(-6)

garik1379 [7]

Answer:

h(-6) = 1

Step-by-step explanation:

Hello!

Substitute -6 for x in the equation.

<h3>Evaluate</h3>

h(x) = -x - 5
h(-6) = -(-6) - 5
h(-6) = 6 - 5
h(-6) = 1

h(-6) is 1.

3 0

1 year ago

You are making a new type of deodorant from two different mixtures the first mixture is 30% smell proof and the second mixture i

Readme [11.4K]

Answer:

600 L of 30% proof and 400 L of 80% proof is needed

Step-by-step explanation:

Let the amount of 30% smell proof be x while that of 80% smell proof is y

Then;

x + y = 1000 •••••(i)

Also;

30% of x + 80% of y = 50% of 1000

0.3x + 0.8y = 500 •••••(ii)

From i, x = 1000 - y

Put this into ii

0.3(1000-y) + 0.8y = 500

300 - 0.3y + 0.8y = 500

0.5y = 500-300

0.5y = 200

y = 200/0.5

y = 400 L

But x = 1000 - y

x = 1000 - 400 = 600 L

3 0

2 years ago

ONLY SERIOUS ANSWERS!!!! 25 POINTS

AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

16x²-169x²+88x+416x+265-400 = 0

-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504± $\sqrt{504^{2}-4(-153)(-135) }$ )/2(-153)

x=(-504± $\sqrt{254016-82620 }$ )/-306

x=(-504± $\sqrt{171396}$ )/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

5 0

3 years ago

Read 2 more answers