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3 years ago

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Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

Step-by-step explanation:

plug in H and J then subtract them which is 1. 6 - 1 = 5

Nataly [62]3 years ago

3 0

Answer:

Step-by-step explanation:

Plug n the h and j so you get 6-(2-1). Due to PEMDAS you do the parenthesis first then subtract so it become 6-1=5. ( You could use distributive property)

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A circle has a diameter with endpoint at 5 + 18i and -3 + 2i. What is the center of the circle?

Alexus [3.1K]

So there is a real and imaginary axis
the midopint is just the average of them
average between the reals is (5-3)/2=2/2=1
average between imaginaries is (18i+2i)/2=20i/2=10i

center is 1+10i

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4 years ago

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Which expressions are differences of squares? Select each correct answer

garri49 [273]

For this ones the second value is always negative so A is not correct. Also they have to have an exact square root which 50 doesn't. So the answers are B and C
(a-6)(a+6)
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3 years ago

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The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

ira [324]

Answer:

The standard deviation would have to be 0.05.

Step-by-step explanation:

We can solve this problem using the 68-95-99.7 rule for normal distributions:

The rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What would the value of σ have to be to ensure that 95% of all readings are within 0.1° of μ?

This means that 2 standard deviations would need to be within 0.1 of the mean. So

$2\sigma = 0.1$

$\sigma = \frac{0.1}{2}$

$\sigma = 0.05$

The standard deviation would have to be 0.05.

6 0

3 years ago

X intercept<br> Of v^2 +5v+6=0

postnew [5]

Answer:

<h2>x-intercepts:</h2><h2>x = -2 and x = -3 ⇒ (-2, 0) and (-3, 0).</h2>

Step-by-step explanation:

$f(v)=v^2+5v+6\\\\\text{The x-intercept is for y = 0.}\\\\v^2+5v+6=0\\\\v^2+2v+3v+6=0\\\\v(v+2)+3(v+2)=0\\\\(v+2)(v+3)=0\iff v+2=0\ \vee\ v+3=0\\\\v+2=0\qquad\text{subtract 2 from both sides}\\v=-2\\\\v+3=0\qquad\text{subtract 3 from both sides}\\v=-3$

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3 years ago

I need help on this h/j=15 for j

4vir4ik [10]

x in (-oo:+oo)

h/j = 15 // - 15

h/j-15 = 0

h*j^-1-15 = 0

x należy do R

x in (-oo:+oo)

8 0

3 years ago

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