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4 years ago

Help with the bottom? thanks ♡

Mathematics

1 answer:

Serggg [28]4 years ago

6 0

2. x³ + 8x + 13
3. 8x + 5
4. 3x² + 2x +4
5. 2x³ + 5x
6. 2x³ - 2x - 6

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What line is parallel to y=1/2x+5

lora16 [44]

theres y=1/2x+7. the line will be parallel as long as you do not change the x value!

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3 years ago

Calculate: 6-[(-3)+(-7)]-[(-1)-(-5)-(-8)]

malfutka [58]

Answer:

The answer is 4

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3 years ago

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Why does 5x2/3 =10x1/3

lesya [120]

Answer:

yes it has

Step-by-step explanation:

The numerators of the eqations equates themselves likewise the denominator

numerators=10

denominators=3

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3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

stealth61 [152]

Answer:

$M_x = 2, M_y = 3$

Center of mass at $(\frac{3}{10},\frac{2}{10})$

Step-by-step explanation:

Given a set of objects $m_1, \dots, m_k$ located at the points $P_1(x_1, y_1), \dots, P_k(x_k,y_k)$ The moments Mx and My are calculated as follows.

$M_x = \sum_{n=1}^k m_n\cdot y_n, M_y = \sum_{n=1}^k m_n\cdot x_n$

and the Center of mass is given at the coordinates $(\frac{My}{M}, \frac{Mx}{M})$ where M is the total mass of the system.

We have that m1=3, m2=4 and m3=3, so M = 3+4+3 = 10.

We have that m1 is at point P1(2,-6), m2 at point P2(-3,2) and m3 at point P3 (3,4), then

$M_x = \sum_{n=1}^k m_n\cdot y_n = 3\cdot(-6)+4\cdot(2)+3\cdot(4)=2$

$M_y = \sum_{n=1}^k m_n\cdot x_n = 3\cdot(2)+4\cdot(-3)+3\cdot(3)= 3$

Then, the center of Mass is at $(\frac{3}{10},\frac{2}{10})$

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3 years ago

7. You bought three erasers and a magazine for $6. You spent a total of $18. How much did

kati45 [8]

Answer:

each eraser cost $4

Step-by-step explanation:

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3 years ago

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