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Akimi4 [234]
3 years ago
14

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

n their school. They select a random sample of 240 students who are asked to complete a survey anonymously. Of these students, 54 report that they have experienced bullying. Use this information to find a 95% ???? ‑confidence interval for ???? , the true proportion of students at this school who have experienced bullying.
Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:   (0.273,\ 0.783)

Step-by-step explanation:

Given : Total number of students who are asked to complete a survey anonymously : n= 240

Number of students

The proportion report that they have experienced bullying =54

Then , the proportion that students have experienced bullying =p=\dfrac{54}{240}=0.225

Significance interval : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

The confidence interval for the true proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.225\pm (1.96)\sqrt{\dfrac{(0.225)(1-0.225)}{240}}\\\\\approx0.225\pm0.0528\\\\=(0.255-0.528,\ 0.255+0.528)\\\\=(0.273,\ 0.783)

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3 years ago
Suppose that news spreads through a city of fixed size of 700000 people at a time rate proportional to the number of people who
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Answer:

y'(t) = k(700,000-y(t))  k>0 is the constant of proportionality

y(0) =0

Step-by-step explanation:

(a.) Formulate a differential equation and initial condition for y(t) = the number of people who have heard the news t days after it has happened.

If we suppose that news spreads through a city of fixed size of 700,000 people at a time rate proportional to the number of people who have not heard the news that means  

<em>dy/dt = k(700,000-y(t)) </em>where k is some constant of proportionality.

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8 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
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|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
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which are complex non-real values


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3 years ago
A 32-ounce package of a snack mix is 24 percent pretzels. How many ounces are pretzels?
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Answer:

0.768 would be the amount of pretzels in ounces

Step-by-step explanation:

24% of 32 =0.768

how i got 24%?

24% of 100= 24

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