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ankoles [38]
3 years ago
15

Juan is going to a school where tuition is $5,000 per year. He has a scholarship that pays 60% of his tuition. He has a grant fo

r $1,000 per year. How much will Juan need to borrow to pay tuition each year?
Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

She now needs to borrow $4000

Step-by-step explanation:

Juan is going to a school where tuition is $5,000 per year. He has a scholarship that pays 60% of his tuition. He has a grant for $1,000 per year. How much will Juan need to borrow to pay tuition each year?

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11. What is the sign of the product of any odd number of
ioda

<u>Explanation:</u>

The sign of the product of any odd number of negative integers is positive because when two minuses are multiplied with each other, it will result in a positive number.

<u>For example:</u>

  • -3 x -5
  • => -1 x -1 x (3 x 5)
  • => 1 x (3 x 5)
  • => 15 (Which is positive)

Hoped this helped!

8 0
3 years ago
How many meters are in 66 ft? <br> 1m = 3.3ft <br> 66ft = ?m
vampirchik [111]

Answer:

20.1168 meters

Step-by-step explanation:

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3 years ago
Find the critical points of the function and use the First Derivative Test to determine whether the critical point is a local mi
Andre45 [30]

Answer:

Critical points are 1 and -1

Maximum at x=1

Minimum at x=-1

Step-by-step explanation:

We are given that a function

f(x)=3tan^{-1}(x)-\frac{3}{2} x+5 on (-\infty,\infty)

We have to find the critical points of the function.

To find the critical point we will differentiate function w.r.t x and then substitute f'(x)=0

f'(x)=\frac{3}{1+x^2}-\frac{3}{2}

\frac{d(tan^{-1}x)}{dx}=\frac{1}{1+x^2}

f'(x)=0

\frac{3}{1+x^2}-\frac{3}{2}=0

\frac{3}{1+x^2}=\frac{3}{2}

1+x^2=2

x^2=2-1=1

x=\pm1

Therefore, the critical points of the given function are 1 and -1.

f(0)=3-\frac{3}{2}=\frac{3}{2}

f'(1)=0

f'(2)=\frac{3}{5}-\frac{3}{2}=-\frac{9}{10}

When we goes from 0 to 2 then the sign of derivative  change from positive to negative .Therefore, function has local maximum at x=1.

f(-2)=\frac{3}{5}-\frac{3}{2}=-\frac{9}{10}

f(-1)=0

f(0)=\frac{3}{2}

When we goes form -2 to 0 then the sign of derivative change from negative to positive .Hence , function has local minimum at x=-1

Hence, critical points are local maximum and local minimum .

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Olivia wants to show 25 with with tens and ones make a list to show the ways
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