How many 3d electrons are in an atom of each element? fe?

1 answer:

8 0

The atomic number of iron, Fe, is 26. This means it has 26 electrons.

Now, as we write the configuration, we come up to electronic subshell 3p, which is completely filled. So the configuration up till this point is identical to Argon, so we may write:

[Ar], 3d, 4s

After the electrons in the Ar configuration are accommodated, there are 8 electrons left for the 3d and 4s shells. The 4s subshell, when empty, is at a lower level than the 3d level, so it fills first. Two electrons are placed here. Therefore, 3d has 6 electrons in Fe.

You might be interested in

What is the definition of the following word sublimitation

DiKsa [7]

the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

6 0

3 years ago

The half reaction of an oxidation-reduction shows that iron gains electrons. What does this electron gain mean or iron?

ale4655 [162]

Answer:

C. its reduced

Explanation:

4 0

3 years ago

Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)

cupoosta [38]

Answer:

$m_{CaCO_3}=0.179gCaCO_3$

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

$PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2$

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

$m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3$

Regards.

3 0

4 years ago

Suppose a thin sheet of zinc containing 0.2 mol of the metal is completely converted in air to zinc oxide (zno) in one month. ho

hram777 [196]

Molecular mass of Zn = 65.38
1 mol = 65 g 
0.2 mol of Zinc = 13.076 g of Zinc 

13.076 g of Zinc is completely converted in air to ZnO in one month
= 13.076 g / 30 days = 0.435 g per day

The rate of conversion of the zinc = 0.44 g / day

8 0

3 years ago

Read 2 more answers

When an organism dies it is exposed to many different types of biotic and abiotic factors biotic factors include?

const2013 [10]

Answer:

the organisms themselves,other organisms,interactions between living organisms, and even their waste.

6 0

3 years ago