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Alexus [3.1K]
3 years ago
12

Suppose a thin sheet of zinc containing 0.2 mol of the metal is completely converted in air to zinc oxide (zno) in one month. ho

w would you express the rate of conversion of the zinc?
Chemistry
2 answers:
hram777 [196]3 years ago
8 0
Molecular mass of  Zn = 65.38  
<span>1 mol = 65 g </span>
<span>0.2 mol of Zinc = 13.076 g of Zinc </span>

<span>13.076 g of Zinc is completely converted in air to ZnO </span><span>in one month
= 13.076 g / 30 days = 0.435 g per day 
</span>
<span>The rate of conversion of the zinc = 0.44 g / day</span>
MissTica3 years ago
7 0

Answer:

r_{Zn}=-kC_{Zn}^2C_{O_2}

Explanation:

Hello,

In this case, the mentioned reaction should be:

2Zn(s)+O_2(g)\rightarrow 2ZnO

In such a way, considering an irreversible reaction and an elemental reaction, the power of each compound's concentration equals the stoichiometric coefficient in its reaction, thus:

r_{Zn}=-kC_{Zn}^2C_{O_2}

It turns out negative since it is a consumption upon zinc.

Best regards.

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