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Leona [35]
3 years ago
11

Phosphours and chlorine react together to produce phosphours trichloride.Which of these is the product in this reaction? A phosp

hours B chlorine. C phosphours trichloride
Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

C. Phosphorus chloride

Explanation:

The product is the thing you get as a result from something else, in this case the reaction of phosphorus and chlorine.

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A sample of carbon-12 has a mass of 6.00 g. How many atoms of carbon-12 are in the sample?
Serjik [45]
<em>mC: 12g/mol</em>

12g ------- 6,02·10²³ a.
6g ---------  X
X = (6×<span>6,02·10²³)/12
</span><u>X = 3,01·10²³ atoms</u>

---->>> A :)

4 0
3 years ago
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In the target above, how would you classify the "hits"? (note: an accurate "hit" is a bull's-eye.)
Dominik [7]
B) Accurate is the right answer
5 0
4 years ago
Silver nitrate has lattice energy of -820kj/mol and a heat of solution of +22.6 kj/mol. calculate the heat of hydration for silv
Genrish500 [490]

Lattice energy = -820 kJ/mole

Heat of solution = +22.6 KJ/mole

Lattice breakdown is and endothermic reaction during the formation of solution

And hydration is an exothermic reaction as ions interact with solvent molecules

By using the formula,

Enthalpy of solution = Lattice energy + hydration energy

Now put the values and calculate,

+22.6 kj/mole = + 820 kj/mole + hydration energy

Hydration energy = 22.6 Kj/mole – 820 Kj/mole

Hydration energy= -797.4 Kj/mole


3 0
4 years ago
A lab team places 0.250g of an unknown solid acid in an Erlenmeyer flask. They neutralize the solid acid with 15.0ml of 0.210 M
Otrada [13]

Answer:

<u>Molar</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>unknown</u><u> </u><u>acid</u><u> </u><u>is</u><u> </u><u>7</u><u>9</u><u> </u><u>grams</u>

Explanation:

We have to first get moles in 15.0 ml of sodium hydroxide solution:

{ \sf{1 \: l \: of \:NaOH \: contains \: 0.210 \: moles }} \\ { \sf{0.015 \: l \: of \: NaOH \: contain \: (0.015 \times 0.210) \: moles }} \\  { \underline{ = 0.00315 \: moles \: of \: NaOH}}

since mole ratio of acid : base is 1 : 1, so;

moles of acid that reacted is <u>0</u><u>.</u><u>0</u><u>0</u><u>3</u><u>1</u><u>5</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>u</u><u>n</u><u>k</u><u>n</u><u>o</u><u>w</u><u>n</u><u> </u><u>a</u><u>c</u><u>i</u><u>d</u><u>.</u>

then we've to get molar mass:

{ \sf{0.00315 \: moles \: of \: acid \: weigh \: 0.250 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 0.250}{0.00315} ) \: g}} \\ { \underline{ = 79.4 \: g \approx79 \: grams}}

6 0
3 years ago
Someone help me with this plz due in 10 minutes ILl give brainly!!!
user100 [1]

Answer:

which one do u want help with?

Explanation:

7 0
3 years ago
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