Using complementary events, considering a 
probability of drawing a red marble, the probability of not drawing a red marble is of 
.
<h3>What are complementary events?</h3>
They are mutually exclusive events which have the sum of their probabilities as 1.
In this problem, we consider that there is a probability of drawing a red marble, and since drawing a red marble and drawing a non-red marble are complementary events, we have that:
The probability of not drawing a red marble is of .
More can be learned about complementary events at brainly.com/question/9752956
Break it down into two parts. First, what is the probability of drawing a blue marble on the first draw?Since there are 5 blue marbles and 10 total, the probability is 5⁄10, or 1/2. Now since we no longer have that blue marble, there are 4 blue marbles and 9 total. The chances of drawing a blue marble are 4/9. Therefore, the chance that both marbles drawn are blue is the chance that the first one is blue times the chance that the second one is blue. 1/2 * 4/9 = 4/18 = 2/9 Remember, math is always trying to trick you. It wants you to try and do the whole big problem at once, which can be difficult. Break it down into smaller problems, then use your answers to small parts to find the answer to the big question. Hope that helps,
